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mihalych1998 [28]
3 years ago
14

Expression evaluate J=-2and k=3

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Well clearly j=2 and k=3

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olchik [2.2K]

Answer:

By sum interior angle of triangle is equal to third exterior angle hence

z = x + y

No find x and y

Sum triangle is 180 degree

5 0
3 years ago
Which statements can be represented by this equation? Select three options.<br> 4<br> 29.2 - 14
MariettaO [177]
The answer is 15.2 hope helps you
6 0
3 years ago
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How does sin 30degrees compare to sin -30degrees?
KiRa [710]

The sine function is an odd function, so the sine of -30° is the opposite of the sine of 30°.

sin(30°) = 1/2

sin(-30°) = -1/2

The sine of 30° is greater than the sine of -30°.

7 0
3 years ago
9x - 7x2 +4x2 - x + 4x3 - 3x2
Anna35 [415]

Answer:

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3 0
4 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
4 years ago
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