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patriot [66]
3 years ago
13

It takes Serina 0.55 hours to drive to school. Her route is 22 km long. What is Serina’s average speed on her drive to school?

Physics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

= 40 km/hr

Explanation:

<u>speed = distance / time</u>

= 22km / 0.55 hr.

= 40 km/hr

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In the diagram below, a box is at rest on an inclined plane.
Sonbull [250]

Answer:

It c

Explanation:

8 0
3 years ago
Joe noted that the temperature in his aquarium dropped overnight. He concluded that thermal energy moved from the aquarium to th
alukav5142 [94]

Answer:

 validate                                            

Explanation:

<u>Law of Conservation of energy</u>

According to the law of conservation of energy, energy of a body or a system gets transferred to another system as different energy. We cannot create energy nor we can destroy energy. Energy is always transformed into other forms of energy.

In the context, Joe noticed that the aquarium's temperature dropped during the night and he concluded that according to the law of conservation of energy, the energy of the aquarium in terms of thermal energy is being transferred to the surrounding air.

This is because the aquarium is considered to be an open system where energy can come in and move out.

Hence Joe's statement is valid.

5 0
3 years ago
Read 2 more answers
A 1.83 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.442 and t
fredd [130]

Answer:7.92 N

Explanation:

Given

mass of book m=1.83\ kg

coefficient of static friction \mu _s=0.442

coefficient of kinetic friction \mu _k=0.240

To move the book, one need to overcome  the static friction  

Static friction F_s=\mu _sN

F_s=\mu _s\times 1.83\times 9.8

F_s=0.442\times 1.83\times 9.8

F_s=7.92\ N

After overcoming the Static friction , Force needed to move the block is

F_k=\mu _kN

F_k=0.240\times 1.83\times 9.8

F_k=4.30\ N

8 0
3 years ago
Debido al desorden en el laboratorio un científico tiene 2 termómetros diferentes pero no sabe en qué escalas están por lo que d
just olya [345]

Answer:

La escala del termómetro ''A'' es grados Celsius.

La escala del termómetro ''B'' es grados Fahrenheit.

Explanation:

Para hallar en qué escalas están los termómetros partimos de que la mezcla a la cuál se midió su temperatura mantuvo su temperatura constante.

Esto quiere decir que los termómetros están expresando la misma temperatura pero en una escala distinta.

Sabemos que dada una temperatura en grados Celsius ''C'' si la queremos convertir a grados Fahrenheit ''F'' debemos utilizar la siguiente ecuación :

F=(\frac{9}{5})C+32 (I)

Ahora, si reemplazamos y asumimos que la temperatura de 18° es en grados Celsius, entonces si reemplazamos C=18 en la ecuación (I) deberíamos obtener F=64.4 ⇒

F=(\frac{9}{5}).(18)+32=32.4+32=64.4

Efectivamente obtenemos el valor esperado. Finalmente, corroboramos que la temperatura del termómetro ''A'' está medida en grados Celsius y la temperatura del termómetro ''B'' en grados Fahrenheit.

6 0
3 years ago
Xenon has an enthalpy of vaporization of 12.6 kJ/mol and a vapor pressure of 1.00 atm at –108.0 °C. What is the vapor pressure o
earnstyle [38]

Answer:

P₁ = 0.0562 atm

Explanation:

Using the Clausius-Clapeyon equation

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)       ------ (eqn 1)

Step 1: From the question given, we state out the parameters given

P₁ = ?                T₁ = -148.0⁰C

P₂ = 1atm          T₂ = -108.0⁰C

ΔHvap = 12.6kJ/mol      R = 8.314J/K.mol

Step 2: Do conversions where necessary for unit consistency since our R value is in J/K.mol

a) convert ⁰C to K

1K = ⁰C + 273.15

T₁ = -148.0⁰C => -148.0⁰C + 273.15

T₁ = 125.15K

T₂ = -108.0⁰C => -108.0⁰C + 273.15

T₂ = 166.15K

b) convert kJ/mol to Joules

ΔHvap = 12.6kJ/mol = 12600Joules

substituting parameters into eqn 1

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)

ln (P₁/1atm) = 12600J / 8.314 (1/166.15 - 1/125.15)

                  = 1515.51 (0.0060 - 0.0079)

                  = 1515.51(-0.0019)

ln (P₁/1atm) = -2.8794

taking exponential of both sides to get rid of the natural log

P₁ = e^ -2.8794

P₁ = 0.05616 atm

P₁ = 0.0562atm

Key Words

1) Clausius-Clapeyon: shows the relationship between pressure and temperature and it is used to estimate the vapour of a solution at a different temperature

5 0
3 years ago
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