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3 years ago

Find the mass of a copper block with heat capacity 50j/kg,(specific heat capacity of copper=400j/kg)

Physics

2 answers:

laiz [17]3 years ago

5 0

The person above me is right listen to then and stan fromis_9

kirza4 [7]3 years ago

3 0

−1
C
−1
and L
f

=3.5×10
5
Jkg
−1

Mass of copper block m=2kg
Heat released by the copper block is equal to the heat gained by the ice to melt.
Let the mass of the ice melted be M.
Change in temperature of copper block ΔT=500−0=500
o
C
∴ mS(ΔT)=ML
f

Or 2×400×500=M×3.5×10
5

⟹ M=1.14kg

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Two 2.0 g plastic buttons each with + 40 nC of charge are placed on a frictionless surface 2.0 cm (measured between centers) on

EleoNora [17]

Answer:

a. There are three potential energy interaction. b. 2.16 m/s c. 2.16 m/s d. 0 m/s

Explanation:

a. There are three potential energy interaction.

Let the charges be q₁ = +40 nC, q₂ = +250 nC and q₃ = + 40 nC and the distances between them be q₁ and q₂ is r, the distance between q₂ and q₃ is r and the distance between q₁ and q₃ is r₁ = 2r respectively. So, the potential energies are

U₁ = kq₁q₂/r, U₂ = kq₁q₃/2r and U₃ = kq₂q₃/r

U = U₁ + U₂ + U₃ = kq₁q₂/r + kq₁q₃/2r + kq₂q₃/r (q₁ = q₃ = q and q₂ = Q)

U = kqQ/r + kq²/2r + kqQ/r = qk/r(2Q + q/2)

b. To calculate the final speed of the left 2.0 g button, the potential energy = kinetic energy change of the particle.

ΔU = -ΔK

0 - qk(2Q + q/2)/r = -(1/2mv² - 0). Since the final potential at infinity equals zero and the initial kinetic energy is zero.

So qk(2Q + q/2)/r = -1/2mv²

v = √[2qk(2Q + q/2)/mr] where m = 2.0 g r = 2.0 cm

substituting the values for the variables,

v = √[2 × 40 × 10⁻⁹ × 9 × 10⁹(2 × 250 × 10⁻⁹ + 40 × 10⁻⁹/2)/2 × 10⁻³ × 2 × 10⁻²]

v = √[360(500 × 10⁻⁹ + 20 × 10⁻⁹)/2 × 10⁻⁵]

v = √[720(520 × 10⁻⁹)/4 × 10⁻⁵] = 2.16 m/s

c. The final speed of the right 2.0 g button is also 2.16 m/s since we have the same potential energy in the system

Since the net force on the 5.0 g mass is zero due to the mutual repulsion of the charges on the two 2.0 g masses, its acceleration a = 0. Since it starts from rests u = 0, its velocity v = u + at.

Hence,

v = u + at = 0 + 0t = 0 m/s

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4 years ago

A baseball of mass 1.23 kg is thrown at a speed of 65.8 mi/h. What is its kinetic energy?

frosja888 [35]

Given:

The mass of the ball is

$m=1.23\text{ kg}$

The speed of the ball is

$\begin{gathered} v=65.8\text{ mi/h} \\ \end{gathered}$

Required: calculate the kinetic energy of the baseball

Explanation: to calculate the kinetic energy of a body we will use the formula as

$K.E=\frac{1}{2}mv^2$

first, we convert velocity from mi/h into m/s.

we know that

$1\text{ mi=1609.34 m}$

and

$1\text{ h=3600 sec}$

then the velocity is

$\begin{gathered} v=\frac{65.8\times1602.34\text{ m}}{3600\text{ s}} \\ v=29.29\text{ m/s} \end{gathered}$

now plugging all the values in the above formula, we get

$\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times1.23\text{ kg}\times(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}$

Thus, the kinetic energy of the baseball is

$527.61\text{ J}$

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2 years ago

2. If it takes Ashley 3 seconds to run from the batter’s box to first base at an average speed of 6.5 meters per second, what is

Semmy [17]

6.5 meters per second mutiplied by 3 seconds and you get 19.5 meters

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3 years ago

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Answer:

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3 years ago

An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid

mariarad [96]

Explanation:

It is given that, An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid Y, along the straight line joining the centers of the asteroids. We need to find the ratio of their masses.

As they are in equilibrium, the force of gravity due to each other is same. So,

$\dfrac{Gm_xM}{r^2}=\dfrac{Gm_yM}{r^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{m_y}=(\dfrac{r_x^2}{r_y^2})\\\\\dfrac{m_x}{m_y}=(\dfrac{140^2}{481^2})\\\\\dfrac{m_x}{m_y}=0.0847$

So, the ratio of masses X/Y is 0.0847

5 0

3 years ago

Find the mass of a copper block with heat capacity 50j/kg,(specific heat capacity of copper=400j/kg)​

Find the mass of a copper block with heat capacity 50j/kg,(specific heat capacity of copper=400j/kg)