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attashe74 [19]
3 years ago
10

Find the mass of a copper block with heat capacity 50j/kg,(specific heat capacity of copper=400j/kg)​

Physics
2 answers:
laiz [17]3 years ago
5 0
The person above me is right listen to then and stan fromis_9
kirza4 [7]3 years ago
3 0

−1
C
−1
and L
f
​
=3.5×10
5
Jkg
−1

Mass of copper block m=2kg
Heat released by the copper block is equal to the heat gained by the ice to melt.
Let the mass of the ice melted be M.
Change in temperature of copper block ΔT=500−0=500
o
C
∴ mS(ΔT)=ML
f
​

Or 2×400×500=M×3.5×10
5

⟹ M=1.14kg
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A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800
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Explanation:

The given data is as follows.

            m = 5000 kg,            h = 800 km = 0.8 \times 10^{6} m

    R_{e} = 6.37 \times 10^{6} m,    r = R + h = 7.17 \times 10^{6} m

   M_{e} = 5.98 \times 10^{24} kg,   G = 6.67 \times 10^{-11} Nm^{2}/kg^{2}

As we know that,

              \frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}

                      v = \sqrt{\frac{GM_{e}}{r^{2}}}

And, it is known that formula to calculate angular velocity is as follows.

               \omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}

                            v = \sqrt{\frac{GM_{e}}{r^{3}}}

                               = \sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}

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Thus, we can conclude that speed of the satellite is 1.0402 \times 10^{-3} rad/s.

6 0
3 years ago
Four point charges have equal magnitudes. Three are positive, and one is negative, as the drawing shows. They are fixed in place
Semmy [17]

Answer:

Ans= 9

See attached picture for clearer solution.

Explanation:

The net electrostatic force acting on charge A = 2/ 2 + 2 /(2) 2 − 2 /(3) 2 = 2 / 2 (1 + 1/4 – 1/9 ) = 41/36 2/2 .  

The net electrostatic force acting on charge B = 2/2 + 2/(2)2 − 2/2 = 1/4 2/d2 .  

The net electrostatic force acting on charge C = 2/2 + 2/(2)2 + 2/2 = 2/2 (1 + 1 4 + 1) = 9/4 2/2 .  

The net electrostatic force acting on charge D = 2/2+ 2 /(2)2 + 2/(3)2 = 2 /2 (1 + 1/4 + 1/9 ) = 49/36 2/ 2 .  

The ratio of the largest to the smallest net force = 9/4*2/2  /  1/4 2/2 . = 9

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shusha [124]
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Answer:

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