-6 (3t - 6) - 3 (11t - 3)

Mathematics

1 answer:

Ronch [10]3 years ago

6 0

Answer:

-51t+45

Step-by-step explanation:

-6(3t-6)-3(11t-3)

-18t+36-33t+9

-51t+45

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Answer:

The value of the first " $5$ " in the number $255,\!120$ is ten times that of the second " $5\!$ " in this number.

Step-by-step explanation:

What gives the number " $255,\!120$ " its value? Of course, each of its six digits has contributed. However, their significance are not exactly the same. For example, changing the first $\verb!5!$ to $\verb!6!$ would give $2\mathbf{6}5,\!120$ and increase the value of this number by $10,\!000$ . On the other hand, changing the second $\verb!5!\!$ to $\verb!6!\!$ would give $25\mathbf{6},\!120$ , which is an increase of only $1,\!000$ compared to the original number.

The order of these two digits matter because the number " $255,\!120$ " is written using positional notation. In this notation, the position of each digits gives the digit a unique weight. For example, in $255,\!120\!$ :

$\begin{array}{|r||c|c|c|c|c|c|}\cline{1-7}\verb!Digit!& \verb!2! & \verb!5! & \verb!5! & \verb!1! & \verb!2! & \verb!0!\\\cline{1-7}\textsf{Index} & 5 & 4 & 3 & 2 & 1& 0 \\ \cline{1-7} \textsf{Weight} & 10^{5} & 10^{4} & 10^{3} & 10^{2} & 10^{1} & 10^{0}\\\cline{1-7}\end{array}$ .

(Note that the index starts at $0$ from the right-hand side.)

Using these weights, the value $255,\!120$ can be written as the sum:

$\begin{aligned}& 255,\!120\\ &= 2 \times 10^{5} + 5 \times 10^{4} + 5 \times 10^{3} + 1 \times 10^{2} + 2 \times 10^{1} + 0 \times 10^{0} \\&=200,\!000 + 50,\!000 + 5,\!000 + 100 + 20 + 0 \end{aligned}$ .