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PilotLPTM [1.2K]
3 years ago
11

A Hudson Valley farmer has 26 employees. He pays each employee $410 per week. After paying his workers for one week, the farmer

has $162 left in his bank account. How much money did he have at first? Show your work with an area model or standard algorithm.

Mathematics
2 answers:
True [87]3 years ago
5 0
He had 10822 because 410 x 10= 10660 and 10660 - 162= 10822
WINSTONCH [101]3 years ago
4 0

Total money the farmer has in the bank before paying the employee is $ 10,822

<h3>Further explanation</h3>

From the problem above, we know that:

Total employee 26 people

Salary/employee $410/week

Total money left after payment $162

How much did the farmer has before he pay the employee?

First step, we are going to calculate total money for payment in one week using the area model method

=\boxed {26 \times410)\ }\\=\boxed {(20+6) \times(400+10)\ }\\ =\boxed {(20 \times400)+(20 \times10)+(6 \times400)+(6 \times10)\ }\\ =\boxed {8000+200+2400+60\ }\\ =\boxed {10660\ }

Total payment at that week is $10660, so if the money left in the bank is $162, total the farmer's money before is

=\boxed {10660+162\ }\\ =\boxed {10822\ }

<h3>Learn more</h3>

Total spend on equipments brainly.com/question/11593405

Total cost for an office space brainly.com/question/7357576

Standard algorithm model brainly.com/question/1150215

Keywords: multiplication, standard algorithm, area model, three digits multiplication, big number multiplication, additional, total spend, math expression, equation

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kicyunya [14]

The correct answer is: 330

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The formula for combination is given as follows:

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Where n = 11

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Plug in the values in equation (1) and calculate:

^nC_r = \frac{n!}{r! (n-r)!} \\ ^{11}C_{4} = \frac{11!}{4! (11-4)!} \\ ^{11}C_{4} = \frac{11*10*9*8*(7!)}{4! (7)!} \\ ^{11}C_{4} = \frac{11*10*9*8}{4!} \\ ^{11}C_{4} = \frac{11*10*9*8}{4*3*2*1} \\ ^{11}C_{4} = 330 \\

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