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alexira [117]
2 years ago
7

-8x+2y=-2 4x+4y=-4 What is the solution to the system

Mathematics
1 answer:
pickupchik [31]2 years ago
3 0

The solution to system is x = 0 and y = -1

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

-8x + 2y = -2 ----------- eqn 1

4x + 4y = -4 ---------- eqn 2

We have to solve the system of equations

We can solve the equations by elimination method

<em><u>Multiply eqn 2 by 2</u></em>

8x + 8y = -8 ------ eqn 3

<em><u>Add eqn 1 and eqn 3</u></em>

-8x + 2y = -2

8x + 8y = -8

( + ) ---------------

0x + 2y + 8y = -2 - 8

10y = -10

Divide both sides by 10

y = -1

<em><u>Substitute y = -1 in eqn 1</u></em>

-8x + 2(-1) = -2

-8x - 2 = -2

-8x = -2 + 2

x = 0

Thus the solution to system is x = 0 and y = -1

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Step-by-step explanation:

Arranging the terms;

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3 years ago
1/2r -3= 3 (4-3/2r) solve for r
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1/2r -3= 3 (4-3/2r) is to be solved for r.


I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.


Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .

Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:


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