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vazorg [7]
3 years ago
10

How do you solve. 9 x + 4 ≤ 103

Mathematics
2 answers:
qwelly [4]3 years ago
7 0

Answer:

x<=11

Step-by-step explanation:

9x+4<=103

-4          -4

9x<=99

x<=11

vivado [14]3 years ago
5 0

Answer:

i think its 11

Step-by-step explanation:

i think you solve it the same way you would to 9x+4=103

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If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
How many roots does the equation (8/(x^2 - 16) )+ 1 = 1/(x -4) have?<br><br> Plz show ALL STEPS
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Answer:

Step-by-step explanation:

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