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ivann1987 [24]
3 years ago
6

Tell whether the argument below is an example of inductive or deductive reasoning.

Mathematics
1 answer:
Lilit [14]3 years ago
6 0

Answer:

Deductive Reasoning

Step-by-step explanation:

We take the statement as true,

"...all dogs in the kennel are collies..."

we also take

- collies are a type of dog

and

- Rover is a dog

So if Rover is a dog, and all dogs in the kennel are collies, then Rover is a collie, because he is a dog and inside the kennel (after we take the statement all dogs in the kennel are collies).

This type of reasoning follows the Deductive Reasoning pattern, if A = B, and B is C then A is also C.

While inductive takes that if A = B, and C is B just like D is B, then E is also B.

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Answer:

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Step-by-step explanation:

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What is 3 root of 125
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There are 1,296 in.2 in one square yard. Use a proportion to find out how many square yards of carpet it would take to cover te
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3 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
As part of a science experiment, Sam recorded the four values shown in the table, but one of them got smudged on his paper. He r
denpristay [2]

Answer:

D) 4

Step-by-step explanation:

−9 + 12 + (unknown) + −8 = −1

<em>Start by going through and testing each option</em>

−9 + 12 + 2 + −8 =

3 + 2 + −8 =

5 + −8 =

−3

−3 ≠ −1

<em>A) 2 is not possible.</em>

−9 + 12 + −2 + −8 =

3 + −2 + −8 =

1 + −8 =

−7

−7 ≠ −1

<em>B) </em>−<em>2 is not possible.</em>

−9 + 12 + −4 + −8 =

3 + −4 + −8 =

−1 + −8 =

−9

−9 ≠ −1

<em>C) </em>−4<em> is not possible.</em>

<em>From this, D is looking like the answer. But to be sure, test it.</em>

−9 + 12 + 4 + −8 =

3 + 4 + −8 =

7 + −8 =

−1

−1 = −1

<em>D) 4 is the answer.</em>

5 0
3 years ago
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