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Rama09 [41]
3 years ago
12

Each of four friends orders a sweatshirt from a catalog. There are 14 colors of sweatshirts, 7 of which are all cotton and 7 of

which are a blend. Each one orders a different color (no repeats) at random. What is the probability that the friends order only cotton sweatshirts?
Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

1/52

Step-by-step explanation:

hope this helps you


Marina86 [1]3 years ago
3 0
Multiply these together: (7/26)*(6/15)*(5/14)*(4/13)
1.92% is the probability all friends order cotton sweatshirts but you can round that up to 2% C'=
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Consider a box that contains 14 red balls,12 blue balls,and 9 yellow balls.A ball is drawn at random and the color is noted and
allochka39001 [22]

Answer:

a. The probability of both balls are blue is \frac{144}{1225}.

b. The probability of getting first red and second yellow ball is \frac{18}{175}.

Step-by-step explanation:

It is given that the box contains 14 red balls,12 blue balls,and 9 yellow balls. The total number of balls is

14+12+9=35

The probability is defined as

p=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}

Probability of getting red ball =  \frac{14}{35}

Probability of getting blue ball =  \frac{12}{35}

Probability of getting yellow ball =  \frac{9}{35}

It is given that a ball is drawn at random and the color is noted and then put back inside the box. It means first event will not effect the probability of second event.

a.

The probability of both balls are blue is

\frac{12}{35}\times \frac{12}{35}=\frac{144}{1225}

b.

The probability of getting first red and second yellow ball is

\frac{14}{35}\times \frac{9}{35}=\frac{18}{175}

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Answer:

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Step-by-step explanation:

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Subtract like terms:

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Put together:

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