Question

The reaction N O space plus thin space O subscript 3 space rightwards arrow space N O subscript 2 space plus thin space O subscript 2 is first order with respect to both NO and O3. The rate constatnt is 2.20 x 107 M-1s-1. If at a given moment, the concentration of NO is 3.3 x 10-6 M and the concentration of O3 is 5.9 x 10-7 M, what is the rate of reaction at that moment

Answer 1

Answer:

4.3 × 10⁻⁵ M s⁻¹

Explanation:

Step 1: Given data

• Rate constant (k):  2.20 × 10⁷ M⁻¹s⁻¹

• Concentration of NO ([NO]): 3.3 × 10⁻⁶ M

• Concentration of O₃ ([O₃]): 5.9 × 10⁻⁷ M

• First order with respect to both NO and O₃

Step 2: Write the balanced reaction

NO + O₃ ⇒ NO₂ + O₂

Step 3: Calculate the reaction rate

The rate law is:

rate = k × [NO] × [O₃]

rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M

rate = 4.3 × 10⁻⁵ M s⁻¹