Im not sure if this will help but... your subscripts in a balanced equation are used to calculate the molar mass of the compound. And your coefficients are used to get the ratios. so for example we have this balanced equation
Be3N2 + 6H2O= 3Be(OH)2 + 2NH3 and you have to find the molar mass of 6h2o, you need to multiply the subscript by the atomic mass and then add them together to get the overall molar mass. * 2(1.01) + 16.00= 18.02 g/mol
and if a question wants to know the limiting or excess regent you would use the coefficients to find out the ratio between the compounds.
Answer:
A process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.
Explanation:
Pretty much just not a physical reaction or otherwise
Answer:
-2024 kJ
Explanation:
The combustion of propane is
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g)
And, ΔG° = ΔH° - TΔS°
Where T is the temperature in K.
ΔH° = ∑n*H°f, reactants - ∑n*H°f, products
Where n is the number of moles in the stoichiometry reaction. H°f, O₂(g) = 0 because it's a substance formed by only one element.
ΔH° = [4*(-226) +3*(-398)] - [-100] = -1998 kJ
ΔS° = ∑n*S°, reactants - ∑n*S°, products
ΔS° = [4*(184) + 3*214] - [5*204 + 271] = 87 J/K = 0.087 kJ/K
So
ΔG° = -1998 - 298*0.087
ΔG° = -2024 kJ
Answer:
<em>The</em><em> </em><em>Typical</em><em> </em><em>Oxidation</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>Oxygen</em><em> </em><em>is</em><em> </em><em>–</em><em>2</em><em>.</em>
<em>And</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>question</em><em> </em><em>said</em><em>.</em><em>.</em><em>.</em><em> </em><em>its</em><em> </em><em>Oxidation</em><em> </em><em>changes</em><em> </em><em>to</em><em> </em><em>–</em><em>1</em><em> </em><em>when</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>Peroxides</em><em> </em><em>and</em><em> </em><em>–</em><em>½</em><em> </em><em>w</em><em>h</em><em>e</em><em>n</em><em> </em><em>i</em><em>t</em><em>s</em><em> </em><em>i</em><em>n</em><em> </em><em>SuperOxides</em><em>.</em>
<em>Correct</em><em> </em><em>Answer</em><em> </em><em>:</em><em> </em><em>Option</em><em> </em><em>D</em><em>.</em>