The local minima of are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)
The function is given as:
See attachment for the graph of the function f(x)
From the attached graph, we have the following minima:
Minimum = (-1.5, 0)
Minimum = (7.980, 609.174)
The above means that, the local minima are
(x, f(x)) = (-1.5, 0) and (7.980, 609.174)
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Answer:
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Step-by-step explanation:
Given that :
Mean = 265
standard deviation = 14
The formula for calculating the z score is
x = μ + σz
At middle of 50% i.e 0.50
The critical value for
From standard normal table
+ 0.67 or -0.67
So; when z = -0.67
x = μ + σz
x = 265 + 14(-0.67)
x = 265 -9.38
x = 255.62
when z = +0.67
x = μ + σz
x = 265 + 14 (0.67)
x = 265 + 9.38
x = 274.38
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Answer:
Step-by-step explanation:
The side that is parallel to BC is EF
Find the slope of EF:
Easiest way is just put the formula in point-slope form and simplify.
Let's use point F, which is (6,2)
Simplify:
Add 2 on both sides:
Hope this helped