The attraction mediated flow of water in the narrow tube has been termed as Capillary action. Thus, option A is correct.
The process of flowing up of liquid with the attraction force between the molecules and the surface has been achieved with the surface characteristics.
<h3>Movement of water in a narrow tube</h3>
The surface has the force of attraction with the flowing liquids in the sample. It results in the increased surface interaction, and the liquid flows up in the tube against gravity.
The movement of the liquid in the water through a narrow tube has been termed as capillary action. Thus, option A is correct.
Learn more about movement of water, here:
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Answer:
blue
Explanation:
KOH is a base therefore it's pH will be above seven. According to table M when tested with the indicator bromcreeol green The solution will turn blue
Given that the volume and amount of water are kept constant,
P/T = constant
P₁/T₁ = P₂/T₂
Normal atmospheric pressure is 746 mmHg and normal boiling point of water is 100 °C.
746/100 = 589/T₂
T₂ = 79.0 °C
CH3 is the empirical formula for the compound.
A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.
The number of atom or moles in the compound is
1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.
0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.
This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.
So we can represent the compound with the formula C0.974H0.284.
Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.
we can divide 0.284 by 0.0974.
0.284 / 0.0974 = 3.
So here, Carbon is one and hydrogen is 3.
We can write the above formula as a CH3.
Hence the empirical formula for the sample compound is CH3.
For a detailed study of the empirical formula refer given link brainly.com/question/13058832.
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