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Readme [11.4K]
3 years ago
15

Terbium-147 undergoes positron emission to become a stable atom. What is that stable atom?

Chemistry
1 answer:
ivanzaharov [21]3 years ago
7 0

We have to get the stable atom formed after positron emission from Terbium-147.

The stable atom is (D) ₆₄Gd¹⁴⁷.

Positron is radioactive decay. Positron is a type of beta particle β⁺.

Positron emission decreases proton number relative to neutron number, positron decay results in nuclear transmutation, changing an atom of one chemical element with an atomic number that is less by one.

Terbium on positron emission produces Gadolinium with one atomic number less than Terbium. So, the positron emission reaction is as shown below:

Tb¹⁴⁷→ ₆₄Gd¹⁴⁷ + ₁e⁰

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Answer : The volume of stock solution needed are, 12.5 mL

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M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

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0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

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