The concentration of A will be <em>0.34 mol·L⁻¹</em> after 60 min.
In a first-order reaction, the formula for the amount remaining after <em>n</em> half-lives is
![\text{[A]} = \frac{\text{[A]}_{0}}{2^{n}}\\](https://tex.z-dn.net/?f=%5Ctext%7B%5BA%5D%7D%20%3D%20%5Cfrac%7B%5Ctext%7B%5BA%5D%7D_%7B0%7D%7D%7B2%5E%7Bn%7D%7D%5C%5C)
If 
∴ ![\text{[A]} = \frac{\text{2.7 mol/L}}{2^{3.0}} = \frac{\text{2.7 mol/L}}{8.0} = \textbf{0.34 mol/L}](https://tex.z-dn.net/?f=%5Ctext%7B%5BA%5D%7D%20%3D%20%5Cfrac%7B%5Ctext%7B2.7%20mol%2FL%7D%7D%7B2%5E%7B3.0%7D%7D%20%3D%20%5Cfrac%7B%5Ctext%7B2.7%20mol%2FL%7D%7D%7B8.0%7D%20%3D%20%5Ctextbf%7B0.34%20mol%2FL%7D)
The answer to this is a carbohydrate compound. Carbohydrates have a general chemical formula of Cₓ(H₂O)ₓ. From the word itself, there is a ratio for every carbon atom that corresponds with the hydrate molecule or water. So, an empirical formula for a carbohydrate is CH₂O which coincides with the 1:2:1 ratio.
Ksp, the product of solubility constant is given by the product of the concentrations in the equilibrium of the species on the right hand of the equillibrium reaction, each raised to a power that is its coeffiicient in the equillibrium reaction.
So you must start by writing the equilibrium reaction:
Fe(OH)3 (s) ----> Fe(3+) aq + 3 (OH-) aq
Now you can state the formula for the Ksp
=> Ksp = [Fe (3+) aq] [OH-]^3
So, the answer is the third option of the list.
Answer:
Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:
