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aliya0001 [1]
3 years ago
9

Jim cuts the grass every 7 days and works in the garden every 3 days. if he cut the grass and worked on the garden on June 1st,

when is the next day that he will do both of these activities?
Mathematics
2 answers:
Mazyrski [523]3 years ago
8 0
Find the least common multiplule
since they are both prime, just multiply them
3*7=21

on June 21 is when he does both
natima [27]3 years ago
6 0
June 22nd is the answer to your question
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I need help with this!!! Thank you
ruslelena [56]

Answer:

4n^3-n^2-5n

Step-by-step explanation:

n(2n+4n2−5−3n)

=(n)(2n+4n2+−5+−3n)

=(n)(2n)+(n)(4n2)+(n)(−5)+(n)(−3n)

=2n2+4n3−5n−3n2

=4n3−n2−5n



6 0
3 years ago
Calculate the distance between the points -11 and 4 on a number<br> line.
krek1111 [17]

Answer:

15, d

Step-by-step explanation:

The absolute value of |-11| + |4| is 11+4 which is 15

5 0
3 years ago
What is the constant of proportionality,<br> ?
zalisa [80]
The constant value (often written k) relating amounts that rise or fall uniformly together. It is the ratio of the amounts y and x: k = y/x. Put another way: y = kx. Example: you are paid $20 an hour.
Hope this helps
Mark as brainliest
8 0
3 years ago
Tim buys a torch and battery the torch costs 11 times as much as the battery Tim pays with a ?10 note and he gets ?4.84 change h
KengaRu [80]

The cost of 1 battery is 0.43

Step-by-step explanation:

Let the cost of 1 battery be x

We are given that the torch costs 11 times as much as the battery

Cost of torch = 11x

Total cost of 1 battery and torch = 11x+x=12x

Tim pays $10

He receives change of $4.84

Total cost of 1 torch and battery = 10 - 4.84 =$5.16

So,12x= 5.16

x= \frac{5.16}{12}

x=0.43

Hence the cost of 1 battery is 0.43

6 0
3 years ago
Graph the circle (x+6)^2 + (y+5)^2 =9
Andrei [34K]

Answer:

This a circle centered at the point (-6,-5), and of radius "3" as it is shown in the attached image.

Step-by-step explanation:

Recall that the standard formula for a circle of radius "R", and centered at the point (x_0,y_0) is given by:

(x-x_0)^2+(y-y_0)^2=R^2

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:

1)  R^2 = 9\,\,\,then\,\,\,R=3  since the radius must be a positive number and (R=-3) is not a viable answer.

2) x_0=-6    for ( x-x_0) to equal   (x+6)

3) y_0=-5    for ( y-y_0) to equal   (y+5)

Therefore, we are in the presence of a circle centered at the point (-6,-5), and of radius "3". That is what we draw as seen in the attached image.

5 0
3 years ago
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