Here you go -12.4 - 5.75 x is your Answer
Answer:
4 units
Step-by-step explanation:
Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
![\it 3x+2y=14 \\ 5x-2y=18 \\ ------\\ 8x \ \ \ \ \ \ \ =32 \Rightarrow x = 32:8\Rightarrow x=4 \ \ \ (*)](https://tex.z-dn.net/?f=%5Cit%203x%2B2y%3D14%0A%5C%5C%0A5x-2y%3D18%0A%5C%5C%0A------%5C%5C%0A8x%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%3D32%20%5CRightarrow%20x%20%3D%2032%3A8%5CRightarrow%20x%3D4%20%5C%20%5C%20%5C%20%28%2A%29)
![\it 3x+2y=14 \stackrel{(*)}{\Longrightarrow} 3\cdot4+2y=14 \Rightarrow 12+2y=14 \Rightarrow 2y=14-12\Rightarrow \\\;\\ \Rightarrow 2y=2 \Rightarrow y=2:2 \Rightarrow y=1](https://tex.z-dn.net/?f=%5Cit%203x%2B2y%3D14%20%5Cstackrel%7B%28%2A%29%7D%7B%5CLongrightarrow%7D%203%5Ccdot4%2B2y%3D14%20%5CRightarrow%2012%2B2y%3D14%20%5CRightarrow%202y%3D14-12%5CRightarrow%20%0A%5C%5C%5C%3B%5C%5C%0A%5CRightarrow%202y%3D2%20%5CRightarrow%20y%3D2%3A2%20%5CRightarrow%20y%3D1)
Therefore, the solution is: x = 4, y=1.
Hi Softballgirl6! I would say that first, we could pretend that the zeros don't exist because we could add those in later. Then just working with 1x2x3x4, we could mentally solve this to 24 and then add in the extra 4 zeros that we left out at the beginning. This brings the answer to 240000. Hope this helps! :)