I = a + (n - 1)d [Given formula]
<h3><u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u>:-</h3>Find d when I = 10, a = 2, n = 5
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>I = a + (n - 1)d [Given]
Putting the value of I = 10, a = 2, n = 5 we get,
10 = 2 + (5 - 1)d
10 = 2 + 4d
10 - 2 = 4d
8 = 4d
d =
d = 2
<h3>Value of d is <u>2</u>. [Answer]</h3>Answer:
Total number of puppies in the litter = 11
Step-by-step explanation:
Let the number of yellow puppies in the litter = y
And the number of black puppies in the litter = b
If there was one less black puppy, ratio of yellow to black puppies =
2(b - 1) = 3y
3y - 2b = -2 -----(1)
If there was one more black puppy, ratio of yellow puppies to black puppies =
2y = b + 1
2y - b = 1 -------(2)
Equation (1) - 2× equation (2)
(3y - 2b) - 2(2y - b) = -2 - 2
3y - 4y - 2b + 2b = -4
y = 4
From equation (1),
3×4 - 2b = -2
12 - 2b = -2
-2b = -14
b = 7
Total number of puppies in the litter = 7 + 4 = 11