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BlackZzzverrR [31]
3 years ago
14

In a certain Algebra 2 class of 26 students, 5 of them play basketball and 12 of them play baseball. There are 12 students who p

lay neither sport. What is the probability that a student chosen randomly from the class plays basketball or baseball?
Mathematics
1 answer:
loris [4]3 years ago
6 0

Answer:\dfrac{7}{13}

Step-by-step explanation:

There are only two games basketball and baseball.

Any student who plays could play basketball or baseball.

Given that there are 26 students in total.

Given that there are 12 students who don't play any game at all.

So,there are 26-12=14 students who play play some baseball or basketball.

Probability=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}

The required probability is \frac{14}{26}=\frac{7}{13}

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Seven people are in an elevator which stops at ten floors. In how many ways can they get off the elevator?
zlopas [31]

The number of ways people can get off the elevator is 604800 ways.

In this question,

Number of people, n = 7

Number of floors, r = 10

The first person can leave elevator in one of 10 ways. Then second person has to choose from one of remaining 9 floors. Then third person in 8, fourth in 7 ways and so on.

Number of ways people can get off the elevator can be calculated as

⇒ nP_r=\frac{n!}{(n-r)!}

⇒ 10P_{7}=\frac{10!}{(10-7)!}

⇒ 10P_{7}=\frac{10!}{(3)!}

⇒ 10P_{7}=\frac{(10)(9)(8)(7)(6)(5)(4)3!}{(3)!}

⇒ 10P_{7}=(10)(9)(8)(7)(6)(5)(4)

⇒ 604800 ways.

Hence we can conclude that the number of ways people can get off the elevator is 604800 ways.

Learn more about number of ways here

brainly.com/question/27992615

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