n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Relationship 2 is a function because x isn’t being repeated.
Answer: a the first answer is right
Answer:
=5/21L+ -5/84
Step-by-step explanation:
=-(5/7) (-(1L/3-3/4)+1/3/4)
=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)
=5/21L= -15/28+ -5/84
=5/21L=+ -25/42
