Find the product of -7-i and its complex conjugate

Mathematics

1 answer:

Alchen [17]3 years ago

8 0

Answer:

Step-by-step explanation:

$-7-i\\\\\text{complex conjugate:}\ -7+i\\\\(-7-i)(-7+i)\qquad\text{use}\ (a+b)(a-b)=a^2-b^2\\\\=(-7)^2-(i)^2\qquad\ i=\sqrt{-1}\to i^2=-1\\\\=49-(-1)\\\\=49+1\\\\=50$

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