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3 years ago

Name the quantity measured by each of the seven si base units and give the si symbol of the unit

Mathematics

1 answer:

Nikolay [14]3 years ago

5 0

Answer:

Length , time, mass, current, temperature, amount of mass, luminous intesity

m, sec, kg, A, K, mol, cd

Step-by-step explanation:

Seven basic SI units are used for measurement of

Meter for length

Second for time

Kilogram for mass

Ampere for current

Kelvin for temperature

Mole for amount of mass

Candela for luminous intensity

Symbols of these SI units are

m for meter

sec for second

kg for kilogram

A for ampere

K for kelvin

mol for mole

cd for candela

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Find the value of x in the following..... 3^x = 8

elena-14-01-66 [18.8K]

Find logarithm of both sides

log (3^x) = log 8

xlog3 = log8

x = log8/log3

x = 1.893

7 0

3 years ago

Read 2 more answers

What is -0.009 to the second power

kondaur [170]

I believe it's -0.000081

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3 years ago

Use the construction in proof of the Chinese reminder theorem to find all solutions to the system of congruence:

antoniya [11.8K]

Answer:

17,101,185, 269,.... is the solution.

i.e. x≡17 mod(84) is the solution

Step-by-step explanation:

Given that the system is

$x ≡ 2 ( mod 3 )x ≡ 1 ( mod 4 )x ≡ 3 ( mod 7 )$

Considering from the last as 7 is big,

possible solutions would be 10,17,24,...

Since this should also be 1(mod4) we get this as 1,5,9,...17, ...

Together possible solutions would be 17, 45,73,121,....

Now consider I equation and then possible solutions are

5,8,11,14,17,20,23,26,29,...,47,....75, ....

Hence solution is 17.

Next number satisfying this would be 101, 185, ...

3 0

3 years ago

Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-half ?

Mice21 [21]

To solve this divide the length and width of the photo by 2. Your new dimensions should be 3in x 4in.

6 0

3 years ago

In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

8 0

3 years ago