Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ = 
L.H.S = sin θ cos θ
so, sin θ cos θ ≠
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Answer:
w=1.4
Step-by-step explanation:
11w+5w-1=65w-36
16w-1=65w-36
16w-65w= -36+1
-49w= -35
w= -35/-49
w= 1.4
The answer to the question is (-3,3)
Answer:
see below
Step-by-step explanation:
translated 3 units down whic means -3 on the y
hence T1 (2,0), T2 (-4,-8), T3 (-2, 1)
Answer:
Step-by-step explanation:
Set it up as fractions, Alex over Peter.
3/5 : 33/x Let x represent Peter's amount. Now find out: how do you get from 3 to 33? What times 3 equals 33? 11
What you do on the top, you must do on the bottom. If 3 times 11 equals 33, then 5 times 11 equals x. 5 times 11 equals 55, so x equals 55.
Peter will get 55. Don't forget the pound symbol.
