In a group of 60 students, 18 students take Algebra I, 20 students take Algebra II, and 10 students take both subjects. How many
1 answer:
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Answer:
It weighs 40 pounds on mars
Step-by-step explanation:
Direct proportion is the relationship between two variables when their ratio is equal to a constant value
- It can be expressed as y = k x, where y varies directly as x and k is constant of variation
- It can be expressed as
∵ The weight of an object on mars varies directly as the weight
of the object on earth
∴ w(m) = k × w(e)
∵ The weight of the object on earth is 75 pound
∴ w(e) = 75
∵ The weight of this object on mars is 25 pounds
∴ w(m) = 25
- Substitute them in the equation of variation
∵ 25 = k × 75
- Divide both sides by 75
∴ = k
∴ w(m) = × w(e)
∵ An object weighs 120 pounds on earth
∴ w(e) = 120
- Substitute it in the equation of variation
∴ w(m) = × 120
∴ w(m) = 40
∴ It weighs 40 pounds on mars
Answer:
Part a) The coordinates of the suspect's car at its final destination are (4,4)
Part b) The distance traveled by the suspect was 10 miles
Part c)
Step-by-step explanation:
The correct question in the attached figure
Part a) What are the coordinates of the suspect's car at its final destination?
we know that
The original position is the origin of a Cartesian coordinate system (0,0)
1) The suspect's car was tracked going 5 mi due east
That means----> 5 mi at right
the new coordinates are (5,0)
2) The suspect's car was tracked going 4 mi due north
That means----> 4 mi up
the new coordinates are (5,4)
3) The suspect's car was tracked going 1 mi due west
That means----> 1 mi at left
the new coordinates are (4,4)
therefore
The coordinates of the suspect's car at its final destination are (4,4)
Part b) What was the distance traveled by the suspect?
The distance traveled is
5 mi due east + 4 mi due north + 1 mi due west
therefore
The distance traveled by the suspect was 10 miles
Part c) What is the distance as the crow flies between the original position and the final position of the suspect's car?
the formula to calculate the distance between two points is equal to
Remember that
The original position was (0,0) and the final position was (4,4)
substitute in the formula
