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Shtirlitz [24]
3 years ago
5

The root of the equation 3x

Mathematics
1 answer:
meriva3 years ago
8 0
Well what’s the entire problem
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Chivis Mexican restaurant pledges 12% of any food purchased on the thrid Wednesday of each month to the cystic fibrosis foundati
Dmitrij [34]

Answer:

food purchased= $9,600

Step-by-step explanation:

Giving the following information:

Chivis Mexican restaurant pledges 12% of any food purchased

Minimum donation= $1,152

<u>To calculate the food to be purchased, we need to use the following formula:</u>

Donation= food purchased*0.12

1,152= food purchased*0.12

1,152/0.12= food purchased

food purchased= $9,600

3 0
3 years ago
janelle and Jacob are considering a $130,000 mortgage for 30 years at 4.8%. With this information, their monthly payment would b
Gala2k [10]

Answer:

sbbz

Step-by-step explanation:

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5 0
3 years ago
A company is paying a local radio station to run its commercials. The cost for running commercials is a one-time campaign fee an
PolarNik [594]
Y = 250 + 100x....the slope is 100

it represents the per second fee of air time...basically, it costs $ 100 per second for the commercial....wow...100 bucks per second....that radio station is making some money.
5 0
3 years ago
Let x be the amount of time (in hours) the wait is to get a table at a restaurant. Suppose the cdf is represented by f(x)=⎧⎩⎨⎪⎪⎪
sattari [20]

Option a is correct. The calculated answer is 0.150

<h3>How to get the value using the cdf</h3>

In order to get  P(0.5 ≤ X ≤ 1.5).

This can be rewritten as

p = 0.5

and P = 1.5

We have the equation as

\frac{1}{16} x^{2}

This would be written as

1.5²/16 - 0.5²/16

= 0.1406 - 0.015625

= 0.124975

This is approximately 0.1250

Read more on cdf here:

brainly.com/question/19884447

#SPJ1

<h3>complete question</h3>

Use the cdf to determine P(0.5 ≤ X ≤ 1.5).

a) 0.1250

b) 0.0339

c) 0.1406

d) 0.0677

e) 0.8750

f) None of the above

4 0
1 year ago
Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)
lisov135 [29]
In short, (h o g)(a) is just h(    g(a)    ).

so what we can do is simply get g(a) first and then plug that in h(x).

\bf \begin{cases}&#10;g(x)&=2x\\&#10;h(x)&=x^2+4\\&#10;(h\circ g)(a)&=h(~~g(a)~~)&#10;\end{cases}&#10;\\\\\\&#10;g(a)=2(a)\implies g(a)=2a&#10;\\\\\\&#10;h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4&#10;\\\\\\&#10;h(~~2a~~)=(2^2a^2)+4\implies  h(~~2a~~)=4a^2+4
8 0
3 years ago
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