An object is thrown upward at a speed of 121 feet per second by a machine from a height of 8 feet off the ground. The height h o
f the object after t seconds can be found using the equation h = -16t^2+121 t+8
When will the height be 17 feet?
When will the object reach the ground?
1 answer:
17=-16t^2+121t+8
16t^2-121t+9=0
this is a quadratic.
it solves to 7.487seconds and 0.075 seconds.
0=-16t^2+121t+8
16t^2-121t-8=0
this solves to 7.628 and -0.066. obviously the time cant be negative so the only real answer is 7.628 seconds
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Answer:
They repesent how to divied
Step-by-step explanation:
A-1538=1074
a=1538+1074
a=2612
b+718=1074
b=1074-718
b=356
2000-c=1074
c=2000-1074
c=926
2612-356+926=3182
8ft by 4ft.
This is because there are 8/4 and 4/4 to make up the blueprint. Therefor you have to multiply the factor by 8 and 4.
-25x is the slope
-42 is the y-intercept