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monitta
3 years ago
6

An object is thrown upward at a speed of 121 feet per second by a machine from a height of 8 feet off the ground. The height h o

f the object after t seconds can be found using the equation h = -16t^2+121 t+8
When will the height be 17 feet?




When will the object reach the ground?
Mathematics
1 answer:
Vladimir79 [104]3 years ago
8 0
17=-16t^2+121t+8
16t^2-121t+9=0
this is a quadratic.
it solves to 7.487seconds and 0.075 seconds.

0=-16t^2+121t+8
16t^2-121t-8=0
this solves to 7.628 and -0.066. obviously the time cant be negative so the only real answer is 7.628 seconds
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<h3>Further explanation</h3>

We will calculate the unit conversion factor used to convert its engine displacement from cubic-centimeters to cubic-inches.

The relationships between inch and cm are as follows:

\boxed{ \ 1 \ inch = 2.54 \ cm\ }

Inches and cm represent units of length.

Made into fractions, 1 inch as the denominator and 2.54 cm as the numerator.

\boxed{ \ \frac{1 \ inch}{2.54 \ cm} \ }

As a unit conversion factor of volume, the numerator and the denominator in cubic.

\boxed{ \ \frac{(1 \ inch)^3}{(2.54 \ cm)^3} \ }

\boxed{ \ \frac{1 \ inch^3}{16.387 \ cm^3} \ }

Thus, we get the unit conversion factor

\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}

Let's use this unit conversion factor to calculate its engine displacement in new units.

\boxed{= 1,043 \ cm^3 \times 0.061 \ \frac{inch^3}{cm^3}}

Note for cm³ units that have been crossed out.

The conversion result is \ \boxed{ \ 63.623 \ inch^3\ }

<h3>Learn more</h3>
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Keywords: the motorcycle engine, Kawasaki Ninja 1000, 1043 cubic-centimeters (cm³), to calculate, its engine displacement, in cubic-inches (in³), what unit conversion factor

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