A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50%50% of this population prefer
1 answer:
Answer:
0.1527
Step-by-step explanation:
Given that a researcher wishes to conduct a study of the color preferences of new car buyers.
Suppose that 50% of this population prefers the color red
15 buyers are randomly selected
Let X be the no of buyers who prefer red.
X has exactly two outcomes red or non red.
Also each buyer is independent of the other
Hence X is binomial with p = 0.5 and n = 15
Required prob =The probability that exactly three-fifths of the buyers would prefer red
= P(X=9)
=
=
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Hello there, today you gave us the problem ,
Our first step is to give them common denominators, which is , solve it and we get
as our answer, which can be simplified down to
She sold 42 oranges with profit 20%
Step-by-step explanation:
The woman sells 90 oranges by RS.160
This price with discount of 20%
We need to find how many oranges she sell by Rs.112 with profit of 20%
- Selling price = cost price - discount ⇒ discount case
- Selling price = cost price + profit ⇒ profit case
Assume that cost price of an orange is x
∵ She sells 90 oranges with Rs.160
- Find the selling price of 1 orange by dividing 160 by 90
∴ The selling price of an orange =
∵ She sold them with discount 20%
∵ The cost price of an orange is x
- Find the 20% of x
∵ Discount = 20% × x = × x = 0.2x
- To find the selling price subtract 0.2x from x
∴ The selling price = x - 0.2x
∴ The selling price of an orange = 0.8x
- Equate 0.8x by to find x
∵ 0.8x =
- Divide both sides by 0.8
∴ x =
Assume that the number of oranges is y
∵ She sell y oranges for Rs.112 with profit 20%
∵ The cost price of an orange is
- Find 20% of
∵ Profit = 20% × =
- Add to cost price to find the selling price
∴ The selling price of an orange = +
∴ The selling price of an orange =
- To find y divide 112 by selling price of an orange
∵ y = 112 ÷
∴ y = 42
She sold 42 oranges with profit 20%
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