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3 years ago

How much would it be worth in 5, 10, 20 years

Mathematics

1 answer:

pochemuha3 years ago

8 0

Answer:

$675

$850

$1200

Step-by-step explanation:

Use formula for simple interest:

A = P (1+rt)

where

A = accrued amount (principal + interest) = what we want to find

P = Principal (initial) amount = Given as $500

r = rate of interest = Given as 7% = 0.07

t = time

For 5 years, t = 5

A = 500 [ 1 + 0.07(5) ] = $675

For 10 years, t = 10

A = 500 [ 1 + 0.07(10) ] = $850

For 20 years, t = 20

A = 500 [ 1 + 0.07(20) ] = $1200

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The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

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The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

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$4p=\frac{3}{2}$

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