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Alex777 [14]
3 years ago
15

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 9% vinegar, and the second brand co

ntains 14% vinegar. The chef wants to make 240 milliliters of a dressing that is 13% vinegar. How much of each brand should he use
Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0
Let the amount of the first brand be x, and let the amount of the second brand be y.
0.09x + 0.14y = 240 * 0.13 .................(1)
x + y = 240 ..............(2)
y = 240 - x .......................(3)
Plugging the value for y from equation (3) into equation (1), we get:
0.09x+0.14(240-x)=240\times0.13 ...............(4)
Equation (4) simplifies to:
-0.05x = -2.4
giving the value for the required amount of 9% vinegar as 48 ml and the required amount of 14% vinegar as 240 - 48 = 192 ml.
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26% is (26-20)/(50-20) = 6/30 = 1/5 of the way between 20% and 50%. That means 1/5 of the solution is 50% acid.

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Maybe you'd like to see an equation. Let x represent the amount of 50% acid required. Then 100-x is the amount of 20% acid needed.  The amount of acid in the mix is ...

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