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Sloan [31]
2 years ago
15

A side of the square is 4t. the area of the square is 400. what is the value of t?

Mathematics
1 answer:
LenaWriter [7]2 years ago
4 0
A side is 4t so A=400=16t^2 by definition. Thus t=5 which produces an area of 400 since [4 (5)]^2=20×20=400.
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F(1) = -16<br> f(n) = f(n-1) · (-1/2)<br> f(3) =
DanielleElmas [232]

Answer:

  -4

Step-by-step explanation:

Use the given value of f(1) to find f(2):

  f(2) = f(1) · (-1/2) = (-16)(-1/2) = 8

Now, we can find f(3) using f(2):

  f(3) = f(2) · (-1/2) = (8)(-1/2)

  f(3) = -4

3 0
3 years ago
PLEASE HELP! I need both and can’t figure out the answer!
zhuklara [117]

Answer:

a) 11.75 * 10^6

b) 1.35 * 10^-7

Step-by-step explanation:

Here, we want to find the sum and the difference

a) That would be;

(3.48 + 8.27) * 10^6

= 11.75 * 10^6

b) That would be;

(9.58-8.23) * 10^-7 = 1.35 * 10^-7

3 0
3 years ago
You have been asked to create a tent for an upcoming trip. The length will be 6ft, the width 4 ft and the height 4ft. Approximat
Aleksandr-060686 [28]

Answer:

I think that it is 88

Step-by-step explanation:

7 0
3 years ago
I really need help!!!!!!!!!!!!!!
krek1111 [17]

Answer:

Step-by-step explanation: After purchasing 21 DVDs the membership is worth the money with a total spending of 104 dollars compared to 105 dollars without the membership.

Membership: -20, -24, -28, -32, -36, -40, -44, -48, -52, -56, -60, -64, -68, -72, -76, -80, -84, -88, -92, -96, -100, -104
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8 0
1 year ago
Evaluate the line integral, where C is the given curve. z2 dx + x2 dy + y2 dz, C C is the line segment from (1, 0, 0) to (4, 1,
N76 [4]

The line integral is the path of the function along a line having a continuous value.

The integral solved gives the value 111.

The given question is

\int\limits^c {z}^2 \, dx+ {x}^2 \, dy+ {y} ^2\, dz

where C is the line from (1, 0, 0) to (4, 1, 3)

Here

x→ 1⇒ 4

y→  0⇒1

z→  0⇒ 3

Let  t be defined be the range  0≤ t ≤ 1

Then x= 4t+1   :    dx= 4dt

y= t                 ":   dy= dt

z= 3t                : dz= 3dt

Putting the values

\int\limits^1_0{9t^2} \, 4dt + \int\limits^1_0 {16t^2+1+8t} \, 3dt +\int\limits^1_0 {t^2} \,3dt

=  [36(1)²- 36(0)²]+ 3 [16(1)² +1+8(1)] - 3 [16(0)² +1+8(0)]  + [3(1)²- 3(0)² ]

= 36 +75-3+3

= 111  

brainly.com/question/16571667

brainly.com/question/18762649

3 0
2 years ago
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