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JulsSmile [24]
3 years ago
9

What are the zeros of the quadratic function f(x) = 6x^2 + 12x – 7?

Mathematics
1 answer:
irinina [24]3 years ago
3 0
<span>6x^2 + 12x – 7 = 0

Use the quadratic formula:

x=  \frac{-b +/-  \sqrt{b^2 -4ac} }{2a}

\frac{-12+/- \sqrt{ 12^{2} -4(6)(-7)} }{12} = \frac{-12+/-17.66}{12}

x = 0.47 and x = -2.47
</span>
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