Question

What are the zeros of the quadratic function f(x) = 6x^2 + 12x – 7?

Answer 1

6x^2 + 12x – 7 = 0

Use the quadratic formula:

$x= \frac{-b +/- \sqrt{b^2 -4ac} }{2a}$

$\frac{-12+/- \sqrt{ 12^{2} -4(6)(-7)} }{12} = \frac{-12+/-17.66}{12}$

x = 0.47 and x = -2.47