All categories

2 years ago

If EF is the perpendicular bisector of CD, find x.

Mathematics

2 answers:

Ksenya-84 [330]2 years ago

5 0

Answer:

Step-by-step explanation:

A Perpendicular Bisector cuts a segment into two equal parts. We already know that 4x+19 and 6x-7 are both equal.

So then, you would start with 6x-7 = 4x+19.

6x-7 = 4x+19

Subtract -4x from both sides

2x-7 = 19

Add 7 to both sides

2x = 26

Divide both sides by two

x= 13

You only need x, so you're done.

(I'm like 90 percent sure this is wrong man don take my word for it bro).

sveticcg [70]2 years ago

5 0

Answer:

x=13

Step-by-step explanation:

4x+19=6x-7

4x=6x-26

4x-6x=6x-26-6x

-2x=-26

\frac{-2x}{-2}=\frac{-26}{-2}

You might be interested in

Solve for x. -1/2 (x+5) = 2x -3/2

Pani-rosa [81]

Answer is a Decimal: x=-0.4

8 0

3 years ago

Can someone please help me. I will give brainliest

d1i1m1o1n [39]

Answer:

B or C hope it helps :)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which of the following shows 2 + (x + 3y) rewritten using the Associative Property of Addition?

Paha777 [63]

B (2+x) +3y

Other examples include (14 + 6) + 7 = 14 + (6 + 7)
because Adding 14 + 6 easily gives the sum of 20 to which we can add 7. The right hand side of the equation is where we add 14 and 13. Both sides will result in 27.

8 0

2 years ago

Which complex number has a distance of radical 17 from the origin on the complex plane?

Inga [223]

Answer: LAST OPTION

Step-by-step explanation:

The complex numbers shown have the form:

$a+bi$

By definition, the distance can the distance of the complex number from the origin on the complex plane can be calculated with the formula shown below:

$d=\sqrt{a^2+b^2}$

Substitute values of each option. Then:

1) $d=\sqrt{2^2+15^2}=\sqrt{229}$

2) $d=\sqrt{17^2+1^2}=\sqrt{290}$

3) $d=\sqrt{20^2+(-3)^2}=\sqrt{409}$

4) $d=\sqrt{4^2+(-1)^2}=\sqrt{17}$ (CORRECT OPTION)

5 0

3 years ago

Read 2 more answers

Central Angles and Arc Measures Practice What is X?

myrzilka [38]

Answer: $5^{\circ}$

Step-by-step explanation:

Given

$\angle DIE=(18x-2)^{\circ}\\\angle DIH=15^{\circ}\\\angle FIG=103^{\circ}$

from the figure

$\angle HIE=\angle GIF\quad [\text{vertically opposite angles}]\\\angle HID+\angle DIE=\angle GIF\\15^{\circ}+(18x)^{\circ}-2^{\circ}=103^{\circ}\\(18x)^{\circ}=103^{\circ}-13^{\circ}\\\\x=\dfrac{90^{\circ}}{18}\\\\x=5^{\circ}$

7 0

2 years ago