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Stella [2.4K]
2 years ago
8

If EF is the perpendicular bisector of CD, find x.

Mathematics
2 answers:
Ksenya-84 [330]2 years ago
5 0

Answer:

Step-by-step explanation:

A Perpendicular Bisector cuts a segment into two equal parts. We already know that 4x+19 and 6x-7 are both equal.

So then, you would start with 6x-7 = 4x+19.

6x-7 = 4x+19

Subtract -4x from both sides

2x-7 = 19

Add 7 to both sides

2x = 26

Divide both sides by two

x= 13

You only need x, so you're done.

(I'm like 90 percent sure this is wrong man don take my word for it bro).

sveticcg [70]2 years ago
5 0

Answer:

x=13

Step-by-step explanation:

4x+19=6x-7

4x+19=6x-7

4x=6x-26

4x-6x=6x-26-6x

-2x=-26

\frac{-2x}{-2}=\frac{-26}{-2}

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Malia runs 5 miles in 1 hour. How many miles does she run in half an hour? In 2 1/2 hours?
Olegator [25]
1/2 hr* (5 miles/ 1 hr)= 2.5 miles.

2 1/2 hrs* (5 miles/ 1 hr)= 12.5 miles.

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2 years ago
!!WILL MARK BRAINLIEST!! <br><br> plz help this is due today
meriva

Answer:

The answer is A

Step-by-step explanation:

3 0
2 years ago
Line segment ST is dilated to create line segment S'T' using the dilation rule DQ,2. 25. Point Q is the center of dilation. Line
abruzzese [7]

The distance between points S' and S is x= 2.5 units.

<h2>Given that</h2>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ 2. 25.

Point Q is the center of dilation.

Line segment ST is dilated to create line segment S prime T prime.

The length of QT is 1. 2 and the length of QS is 2.

The length of SS prime is x and the length of TT prime is 1. 5.

<h3>We have to determine</h3>

What is x, the distance between points S' and S?

<h3>According to the question</h3>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ, 2.25.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5, SS' = x.

Since the line ST is dilated to S'T' with the center of dilation Q, the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q.

\dfrac{SQ}{S'Q} = \dfrac{TQ}{T'Q}\\&#10;\\&#10;\dfrac{SQ}{SQ+SS} = \dfrac{TQ}{TQ+TT'}\\&#10;\\ &#10;\dfrac{2}{2+x} = \dfrac{1.2}{1.2+1.5}\\\rm &#10;\\&#10;\dfrac{2}{2+x} = \dfrac{1.2}{2.7}\\\\ \dfrac{2}{2+x} = \dfrac{12}{27}\\\\2(27) = (2+x) 12\\\\ 54 = 24 + 12x\\&#10;\\&#10;12x = 54-24\\&#10;\\&#10;12x=30\\&#10;\\&#10;x = \dfrac{30}{12}\\&#10;\\&#10;x = 2.5

Hence, the distance between points S' and S is x= 2.5 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/16016926

5 0
2 years ago
What are the sine and cosine ratios for a 30°–60°–90° triangle with a hypotenuse of 6, when θ = 60°?
Margaret [11]

Answer:

There are two ways to do this problem algebraically or trigonometrically.

Algebraically/geometrically

The ratios of the sides of a 30/60/90 tri. are x, x√3, 2x (short leg, long leg, hyp). Therefore, if the long leg is 6 'units'. then 6 = x√3. x = 6√3.

The hyp is 2x then the hypotenuse is 2(6√3) = 12√3, rationalizing is 12√3/3 = 4√3

Using Trig.

We can use sinx = y/r = opp/hyp. The long leg of 6 is opposite 60 degrees (pi/3).

Therefore, sin(pi/3) = 6/r =

r = 6/sin(pi/3) = 6/(√3/2) = 12/√3, when you rationalize you get 12√3/3 = 4√3

4 0
2 years ago
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