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jolli1 [7]
3 years ago
6

Simplify the expression sin^2 x-1/ cos(-x)

Mathematics
1 answer:
laila [671]3 years ago
5 0
\hbox{using trigonometric identities:} \\ \sin^2x +\cos^2x=1 \\ \sin^2x=1-\cos^2x \\ and \\ \cos (-x)=\cos x \\ \\ \frac{\sin^2x-1}{\cos (-x)}=\frac{1-\cos^2 x-1}{\cos x}=\frac{-\cos^2x}{\cos x}=\boxed{- \cos x} \\
(x \not= \frac{\pi}{2}+n\pi, n \in \mathbb{Z})
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Please help me Fill in the blank with a variable term to make the equation true
aleksandr82 [10.1K]

Answer:

x = 6

2x+3=15

2x=12

x=6

therefore,

6x+3=15

3 0
4 years ago
What is the domain of the function
Anon25 [30]
The answer is -2,2,3,4
7 0
3 years ago
What is an equation of the line that passes through the point (-7,-6)(−7,−6) and is parallel to the line x-y=7x−y=7?
kotykmax [81]

Answer:

y = x + 1

Step-by-step explanation:

The gradient of a line can be defined by the equation:

m (gradient) = (y1 – y2 ) ÷ (x1 – x2) ----> "1" and "2" should be in subscript

For (-7,-6) we use x2 and y2 (because this point can be anywhere along a line):

x2 = -7, y2 = -6

Plug these values into the formula above:

m = (y-(-6)) ÷ (x-(-7))

m = (y+6) ÷ (x+7)

At this stage, the equation can't be solved as there are two unknowns. Therefore, the gradient must be found another way. Two lines are parallel if they have the same gradient - in their y=mx+c equations, m will be equal.

x - y=7 is the line alluded to in the question. Rearranging this equation into the line equation format gives:

y = x-7 ---> The gradient (coefficient of x) is 1.

Therefore, the gradient of the other parallel line must also be 1.

This can be substituted into the previous equation to give:

1 = (y+6)÷(x+7)

x+7 = y+6

x+1 = y

Therefore, the answer is y=x+1

5 0
3 years ago
I need help on that question ​
Anika [276]

Answer:

the required answer is

80 \sqrt{3}

Step-by-step explanation:

here's the solution : -

=》

4 \sqrt{5}  \times 4 \sqrt{15}

=》

4 \sqrt{5}  \times 4 \sqrt{5}  \times  \sqrt{3}

=》

4 \times 4 \times 5 \times  \sqrt{3}

=》

80 \sqrt{3}

3 0
3 years ago
Read 2 more answers
The area beyond ± 2 standard deviations contains approximately what % of the area under the normal curve?
irakobra [83]
A. 99%
Enjoy the holidays :)
7 0
4 years ago
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