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AnnZ [28]
3 years ago
13

The difference between twice a number and 2

Mathematics
2 answers:
Brums [2.3K]3 years ago
6 0

2x-2

The difference between(subtract)

Twice a number(2x)

and 2

Pie3 years ago
3 0

Answer:

2 is a number and "twice a number" means multiply by 2.

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Caroline puts $400 into a savings account that earns 6% annually. Write a function that represents this situation, where t is th
DaniilM [7]

Answer: 19 years

Step-by-step explanation:

Given

Amount invested \$400

Rate of interest R=6\%

after 1-year amount becomes

A=400\left (1+6\%\right)\\A=400\left (1+0.06\right)\\A=400\times 1.06\\A=\$424

After n years it is

A=400\left (1.06\right)^n

Sum accumulated is \$1200

\Rightarrow 1200=400\left(1.06\right)^n\\\Rightarrow 3=\left(1.06\right)^n\\\text{Taking log both sides}\\\Rightarrow n=\dfrac{\ln 3}{\ln 1.06}\\\\\Rightarrow n=18.85\approx 19\ \text{years}

5 0
3 years ago
3f+2g=30 and f+2g=26
tatuchka [14]
3f + 2g = 30 . . .(1)
f + 2g = 26 . . . .(2)

(1) - (2) => 2f = 4 => f = 4/2 = 2

From (2), 2 + 2g = 26 => 2g = 26 - 2 = 24 => g = 24/2 = 12

Therefore, f = 2 and g = 12
7 0
3 years ago
6у – 6 = 4у + 16<br> A.y=2.2<br> B. y= -2.2<br> C. у= 11<br> D. у= 5
Korvikt [17]

Answer:

C. y=11

Step-by-step explanation:

6y-6=4y+16

6y=4y+22

2y=22

y=11

7 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
What is the solution to x- 9&gt; -15?
Elanso [62]

Answer:

x < -6

Step-by-step explanation:

quick explanation: when you transfer (-9) to the other side it becomes +9.

Therefore, -15+9= -6

4 0
3 years ago
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