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Zina [86]
3 years ago
14

A sack of cement is enough to cover a floor with a total area of 45sqft Joel’s floor length is 8ft by 7ft how many sacks will he

need to cover his entire floor?
Mathematics
1 answer:
borishaifa [10]3 years ago
8 0

2 sack of cement is needed to cover entire floor of Joel

<em><u>Solution:</u></em>

Given that a sack of cement is enough to cover a floor with a total area of 45 sqft

Joel’s floor length is 8ft by 7ft

To find: Number of sacks needed to cover entire floor of Joel

Let us first find area of Joel's floor

Since the floor is generally of rectangular, we can use area of rectangle

\text{ area of rectangle } = length \times width

<em><u>So the total area of floor with length 8 feet and width 7 feet is:</u></em>

\text{ area of floor } = 8 \times 7 = 56

Thus the total area of floor is 56 square feet

<em><u>Let us now find number of sacks needed to cover entire floor</u></em>

Given that, one sack of cement covers 45 square feet

\text{ number of sacks needed } =\frac{\text { total area of floor }}{\text { area covered by one sack }}$

\text{ number of sacks needed }=\frac{56}{45}=1.244$

Since Sack of cement cannot be in point value hence we can say 2 sack of cement is required.

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Answer:

-7 3/8

Step-by-step explanation:

The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

-\frac{8}{3}+\left(-\frac{1}{4}\right)+\left(-\frac{11}{6}\right)+\frac{3}{8}-3\\=-\frac{64}{24}+\left(-\frac{6}{24}\right)+\left(-\frac{44}{24}\right)+\frac{9}{24}-3\\\\=\frac{-64+(-6)+(-44)+9}{24} -3\\\\=\frac{-70+(-44)+9}{24} -3\\\\=\frac{-114+9}{24} -3\\\\=\frac{-105}{24}-3 \\\\=\frac{-35}{8}-3\\ \\=-4\frac{3}{8}-3\\\\=-7\frac{3}{8}

So our solution is -7 3/8

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3 years ago
Which category of two-dimensional shapes apply to all three of these shapes?
fomenos

Answer:

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Step-by-step explanation:

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4 0
3 years ago
What is the best estimate of 45 percent of 76
marishachu [46]

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Step-by-step explanation:

Well, 45% of 76 is 34.2

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The closest one is 1/5(80) which solves the estimate,

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