Solve for x: 3x + 3 = -2x + 13

Mathematics

1 answer:

kobusy [5.1K]3 years ago

8 0

Answer:

x=2

Step-by-step explanation:

To solve, we need to isolate the variable (x)

To do this, we must get all the variables to one side of the equation, and all the numbers to the other

3x+3= -2x+13

Add 2x to both sides to "reverse" the subtraction

5x+3=13

Subtract 3 from both sides to "reverse" the addition

5x=10

Divide both sides by 5 to "reverse" the multiplication

x=2

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75 points. Will give certified if work is shown and the answer is correct.

Svetach [21]

Volume of the first dwarf planet (r₁ = 832 mi):

$V_1=\dfrac{4}{3}\cdot\pi\cdot r_1^3=\dfrac{4}{3}\cdot\pi\cdot 832^3=\dfrac{2303721472}{3}\pi\approx7.679\cdot10^8\pi\,\text{mi}^3$

Volume of the second dwarf planet (r₂ = 829 mi):

$V_2=\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\cdot\pi\cdot 829^3=\dfrac{2278891156}{3}\pi\approx7.5963\cdot10^8\pi\,\text{mi}^3$

So difference between the volumes is:

$V_1-V_2\approx7.679\cdot10^8\pi-7.5963\cdot10^8\pi=0.0827\cdot10^8\pi=\boxed{8270000\pi\,\text{mi}^3}$

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):

$V_1-V_2=\dfrac{4}{3}\cdot\pi\cdot r_1^3-\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\pi(r_1^3-r_2^3)=\dfrac{4}{3}\pi(832^3-829^3)=\\\\\\=\dfrac{4}{3}\pi(832-829)(832^2+832\cdot829+829^2)=\\\\\\=\dfrac{4}{3}\pi\cdot3(692224+689728+687241)=4\pi\cdot2069193=\boxed{8276772\pi\,\text{mi}^3}$

3 0

3 years ago

I WILL GIVE BRAINLIEST, 5 STARS, AND THANKS!

elixir [45]

Answer:

D. 27

Step-by-step explanation:

1.5 cm / 0.5 cm = 3

So now think of the cube as 3 blocks x 3 blocks x 3 blocks, instead of 1.5cm x 1.5cm x 1.5cm. 3 x 3 x 3 = 27

I hope this helped!

6 0

3 years ago