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3 years ago

Can you solve this for me by:

1 answer:

7 0

$2a^2-32$

$2*a^2-2*16$

$2*(a^2-16)$

but we have a Difference of two square

$x^2-y^2=(x+y)*(x-y)$

now you can see it very well

$2*(a^2-4^2)$

so

$\boxed{\boxed{2*(a-4)*(a+4)}}$

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PLEASE HELP IM STUCK

stellarik [79]

Answer:

-2

Step-by-step explanation:

The slope of a line is rise/run

So, just see how much the line rises/how much the line runs

In this case, the line rises 2 units for every -1 unit it runs

So, the slope is -2

7 0

2 years ago

You are having a conference call with the CEO of a paper company. You have interpreted the number of trees cut down versus profi

loris [4]

You can only cut down a integer number of trees. So you might look at a few integer values for x. As x get large the –x4 term dominates the expression for big losses. x = 0 is easy P(x) = -6. Without cutting any trees you have lost money Put x = 1 and you get for the terms in order -1 + 1 + 7 -1 -6 = 0. So P(x) crosses zero just before you cut the first tree. So you make a profit on only 1 tree. However when x=10 you are back into no profit. So compute a few values for x = 1,2,3,4,5,6,7,8,9.

8 0

3 years ago

Read 2 more answers

Graph the inequality: –10 < t < 5

shusha [124]

Answer:

no lo sé perdón buen día puto hgfhkghhhddj

Step-by-step explanation:

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7 0

3 years ago

What is the GCF 16 24 40

boyakko [2]

The factors of 16 are 1, 2, 4, 8, and 16.
The factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24. 
The factors of 40 are 1, 2, 4, 5, 8, 10, 20, and 40. 
So the greatest common factor of 16, 24, and 40 is 8.

Hope this helps:)

4 0

3 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago