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dem82 [27]
3 years ago
11

Need the answer thanks

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

The correct answer is A) y+2x=0

(Graph to show answer)

A is red

B is blue

C is green

D is purple

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SOLVE STEP BY STEP !!!! answer correctly please !! Will mark brainliest !!!!!!!!!!!!!!
Mnenie [13.5K]

Step-by-step explanation:

(3X-20)+(3X+5)=111(( SINCE 111 IS TOTAL ANGLE

6X-15=111

6X=126

X=21

EFG=3×21-20

=63-20=43

8 0
3 years ago
Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap
inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = 3.6e^{-j33.7^{\circ}}

zz = - 4 + j3 = 5e^{j143.1^{\circ}}

Part b:

|zj| = |3− j2| =  √3² +(−2)² = √13 = 3.60

|z1| =  √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = 3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}

6 0
3 years ago
What are the discontinues of the function f(x) = x^2 - 16/6x-24
Mumz [18]
The function f(x) = (x^2 - 16) / (6x - 24) is discontinuos at
6x - 24 = 0
6x = 24
x = 4.
3 0
4 years ago
To classify
Talja [164]

Answer:

The system of linear equations consist of parallel lines

Step-by-step explanation:

Here, we want to classify the system of linear equations

Firstly, let us write both in the standard forms

For the first;

y = 3x + 2

For the second;

y = 3x-1

The general form of a linear equation is;

y = mx + b

where m is the slope and b is the y-intercept

In both cases, m = 3 and that means the slope is the same

When two lines have same slope values, they are said to be parallel to each other

7 0
3 years ago
Which of the following is an example of a quadratic equation
raketka [301]

Answer:

x

2

=36x, start superscript, 2, end superscript, equals, 36

(x-2)^2=49(x−2)

2

=49left parenthesis, x, minus, 2, right parenthesis, start superscript, 2, end superscript, equals, 49 [Why is this a quadratic equation?]

x^2

x, start superscript, 2, end superscript(x-2)^2

left parenthesis, x, minus, 2, right parenthesis, start superscript, 2, end superscriptxx

\begin{aligned}(x-2)^2&=49\\\\ x^2-4x+4&=49\end{aligned}

 

x^2

x, start superscript, 2, end superscript

2x^2+3=1312x

2

+3=131

Step-by-step explanation:

8 0
4 years ago
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