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dem82 [27]
3 years ago
11

Need the answer thanks

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

The correct answer is A) y+2x=0

(Graph to show answer)

A is red

B is blue

C is green

D is purple

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What’s (-3 , 1) reflected over the x-axis
Oxana [17]

Answer: (-3,-1)

Step-by-step explanation:

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3 years ago
F(x)=|2x+1|+3<br> g(x)=-2<br><br> find (f+g)(x)
marysya [2.9K]

Answer:

Fdnxi x (f+g)

Step-by-step explanation:

7 0
3 years ago
The probability that a randomly chosen person has a dog is 0.34. The probability that a randomly chosen person will have a dog a
Elina [12.6K]

Taking into definition of probability, the probability that a randomly chosen person is not walking in the park is 0.91.

<h3>Definition of Probabitity</h3>

Probability is the possibility that a phenomenon or an event will happen, given certain circumstances. It is expressed as a percentage.

<h3>Union of events</h3>

The union of events, AUB, is the event formed by all the elements of A and B. That is, the event AUB is verified when one of the two, A or B, or both occurs. AUB is read as "A or B".

The probability of the union of two compatible events is calculated as the sum of their probabilities subtracting the probability of their intersection:

P(A∪B)= P(A) + P(B) -P(A∩B)

<h3>Complementary event</h3>

A complementary event is made up of the inverse of the results of another event. That is, That is, given an event A, a complementary event is verified as long as the event A is not verified.

The probability of occurrence of the complementary event A' will be:

P(A´)= 1- P(A)

<h3>Events and probability in this case</h3>

In first place, let's define the following events:

  • D: a person has a dog.
  • W: a person is walking in the park.

Then you know:

  • P(D)= 0.34
  • P(D and W)= P(D∩W)= 0.03 [The intersection of events, A ∩ B, is the event formed by all the elements that are, at the same time, from A and B. That is, the event A ∩ B is verified when A and B occur simultaneously.]
  • P(D or W)= P(D∪W)= 0.40

In this case, considering the definition of union of eventes, the probability that a randomly chosen person is walking in the park is calculated as:

P(D∪W)= P(D) + P(W) -P(D∩W)

0.40= 0.34 + P(W) -0.03

Solving:

0.40= 0.31 + P(W)

0.40 - 0.31= P(W)

<u><em>0.09= P(W)</em></u>

Then, the probability that a randomly chosen person is walking in the park is 0.09.

Considering the definition of the complementary event and its probability, the probability that a randomly chosen person is NOT walking in the park is calculated as:

P [W']= 1- P(W)

Replacing and solving:

P [W']= 1 - 0.09

P [W']= 0.91

Finally, the probability that a randomly chosen person is not walking in the park is 0.91.

Learn more about probability:

brainly.com/question/25839839

brainly.com/question/26038361

#SPJ1

7 0
2 years ago
What value of x makes the function {(1,5), (x,8), (-7,9)} a function?
mestny [16]
X can be anything you want as long as it is not 1 or -7. If you have repeated x values with different y values, then it won't be a function. 
5 0
4 years ago
How do I do these? I don’t understand how my teacher is teaching it so can someone explain
Mamont248 [21]

Here's some guidelines to help you:

For 1, 4, 5, and 6, they are 30-60-90 triangles. What's that you may ask? Well, it means that the sides have a predetermined length when one side is given. In #1 for example, you have a side of 11sqrt3, this means that "n" is 11 because in a 30-60-90 triangle, the longer side is the sqrt3 times the length of the shorter side. So to get the shorter side, we divide by sqrt3 to get 11. "m", or the hypotenuse, can be determined by taking twice the length of the shorter side. Since we figured out earlier that the shorter side is 11, 11 times 2 is 22. So the answer for #1 is n=11, m=22.

For 2 and 3, they are 45-45-90 triangles, triangles where the two lengths are the same and the hypotenuse is either leg length times sqrt2. In problem #2 for example, "y" must be 17 because one leg length is 17. "x", or the hypotenuse, is equal to 17sqrt(2) because 17 times sqrt(2).

You can apply all these rules to the other 4 problems I didn't explain.

Hope this long explanation clears your doubts!

5 0
3 years ago
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