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dem82 [27]
3 years ago
11

Need the answer thanks

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

The correct answer is A) y+2x=0

(Graph to show answer)

A is red

B is blue

C is green

D is purple

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Simplify completely 25 w to the sixth power over 10 w to the third power divided by 30 w squared over 5 w.
malfutka [58]
\cfrac{25w^6}{10w^3}:  \cfrac{30w^2}{5w}=  \cfrac{5w^3}{2}*  \cfrac{5w}{30w^2}= \cfrac{w}{2}*  \cfrac{5w}{6}= \cfrac{5w^2}{12}
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3 years ago
Read 2 more answers
Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

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3 years ago
Given the equation p2 = a3, what is the orbital period, in days, for the planet venus? (venus is located 0.72 au from the sun?)
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Hello,
P=0.72^(3/2)=0.610940...years=223.1398...days
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A store owner purchases thirty 75-watt light bulbs and 40 fluorescent light bulbs for a total cost of $95. A second purchase, at
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Answer:   75-watt are 30$  fluorescent are 30$ in the second and 65$ in the first

     

Step-by-step explanation: i calculated thirty 75-watt and the fluorescent and got these kinda hard to explain hope i helped:)

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Factor completley x2-4x-12
Artist 52 [7]

Step-by-step explanation:

The answer is 4x

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