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Tems11 [23]
3 years ago
5

What is the first step in solving 3a+b=225?

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
Writing the equation down
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The approximate distance between J and K is units. The approximate distance between K and L is units. The approximate distance b
Dima020 [189]
Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
{a}^{2}  +  {b}^{2}   =   {c}^{2}
Plug in the numbers:
{4}^{2}  +  {3}^{2}  =  {c}^{2}   \\  \\ = 16 + 9  \\  \\ = 25 \\  \\ c =  \sqrt{25}  = 5
c is 5.

Same thing with g:
{e}^{2}  +  {f}^{2}  =  {g}^{2}  \\  \\    {g}^{2} = {4}^{2}  +  {4}^{2}  \\  \\  = 16 + 16 \\  \\  = 32 \\  \\ g =  \sqrt{32} = 4 \sqrt{2}  = 5.66
g equals 5.66.

7 0
4 years ago
Solve.<br><br>10.8 - (-6.4) ×3​
Artist 52 [7]

Answer:

51.6

Step-by-step explanation:

10.8 - -6.4 is 17.2

17.2 x 3 is 51.6

4 0
3 years ago
Read 2 more answers
1-2 Cos²25°÷(1-2sin²25)<br>​
shusha [124]

Answer:

have a good one

Step-by-step explanation:

6 0
2 years ago
Here are the monthly charges for jo’s Mobile phone. Monthly charge £16,150 free minutes,then 13p per minute,150 free texts,then
zhuklara [117]

Answer:

16,652

Step-by-step explanation:

5 0
3 years ago
Center (-15,11) radius 2
kodGreya [7K]

Answer:

(x+15)^2+(y-11)^2=4

Step-by-step explanation:

<u><em>The question is</em></u>

How do you write an equation for a circle with center (-15,11) and radius 2?

we know that

The equation of a circle in center radius form is given by

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

substitute the given vales

(x+15)^2+(y-11)^2=2^2

(x+15)^2+(y-11)^2=4

8 0
3 years ago
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