Answer:
The mistake McGill made was to eliminate 4 and 16 from both sides before solving fro x
Step-by-step explanation:
Given the expression
42x = 163
To get the values of x, we are to divide both sides by the coefficient of x i.e 42 as shown;
42x = 163
42x/42 = 163/42
x = 163/42
x = 3.88
Hence the mistake McGill made was to eliminate 4 and 16 from both sides before solving fro x
Answer:
f/g at t =3 will be 9/8
d/ddx(f(x)/g(x))=f'(x)d(x)-f(x)g'(x)/(g'(x))^2
rate of change=(6*8)+(9*9)/9^2
rate of change =43/27=1.5925
So, that's

*Helpful To Know
![{5}^{ \frac{1}{2} } = \sqrt{5} \\ {5}^{ \frac{1}{3} } = \sqrt[3]{5} \\ {5}^{ \frac{1}{4} } = \sqrt[4]{5} \\ {5}^{ \frac{3}{2} } = \sqrt{ {5}^{3} } \: \: or \: {( \sqrt{5} )}^{3}](https://tex.z-dn.net/?f=%7B5%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B5%7D%20%5C%5C%20%20%7B5%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B5%7D%20%20%5C%5C%20%7B5%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B5%7D%20%20%20%20%5C%5C%20%20%20%7B5%7D%5E%7B%20%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%20%7B%28%20%5Csqrt%7B5%7D%20%29%7D%5E%7B3%7D%20)
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*Assuming that you want to covert to radicals
![( \sqrt{8} )( \sqrt{x} )( \sqrt[4]{ {y}^{3} } )](https://tex.z-dn.net/?f=%28%20%5Csqrt%7B8%7D%20%29%28%20%5Csqrt%7Bx%7D%20%29%28%20%5Csqrt%5B4%5D%7B%20%7By%7D%5E%7B3%7D%20%7D%20%29)
*Simplify
Step-by-step explanation:
3c + 3s = 12.50
4c + 2s = 10.00
3S = 12.50-3c
s = 4.17 - c
4c + 2 (4.17-c) = 10.00
2c + 8.34 = 10.00
2c = 1.66
chips = 0.83
soda = 3.34
Answer:
To find the answer, you multiply 5 by itself 5 times as follows: 5 x 5 x 5 x 5 x 5 =. And you get the answers which is. 3,125. Note that 5 to the power of 5 is the same as 5 raised to 5. In x y, 5 is the base (x) and 5 is the exponent (y) and you can therefore also write the problem and the answer as follow: 5 5 = 3,125.
Step-by-step explanation:
hope it helps? :))