Answer:
93% probability of a student taking a calculus class or a statistics class
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a student takes a calculus class.
B is the probability that a student takes a statistics class.
We have that:
![A = a + (A \cap B)](https://tex.z-dn.net/?f=A%20%3D%20a%20%2B%20%28A%20%5Ccap%20B%29)
In which a is the probability that a student takes calculus but not statistics and
is the probability that a student takes both these classes.
By the same logic, we have that:
![B = b + (A \cap B)](https://tex.z-dn.net/?f=B%20%3D%20b%20%2B%20%28A%20%5Ccap%20B%29)
The probability of taking a calculus class and a statistics class is 0.07
This means that ![A \cap B = 0.07](https://tex.z-dn.net/?f=A%20%5Ccap%20B%20%3D%200.07)
The probability of taking a statistics class is 0.90
This means that
. So
![B = b + (A \cap B)](https://tex.z-dn.net/?f=B%20%3D%20b%20%2B%20%28A%20%5Ccap%20B%29)
![0.9 = b + 0.07](https://tex.z-dn.net/?f=0.9%20%3D%20b%20%2B%200.07)
![b = 0.83](https://tex.z-dn.net/?f=b%20%3D%200.83)
The probability of a student taking a calculus class is 0.10
This means that ![A = 0.1](https://tex.z-dn.net/?f=A%20%3D%200.1)
![A = a + (A \cap B)](https://tex.z-dn.net/?f=A%20%3D%20a%20%2B%20%28A%20%5Ccap%20B%29)
![0.1 = a + 0.07](https://tex.z-dn.net/?f=0.1%20%3D%20a%20%2B%200.07)
![a = 0.03](https://tex.z-dn.net/?f=a%20%3D%200.03)
What is the probability of a student taking a calculus class or a statistics class
![A \cup B = a + b + A \cap B = 0.03 + 0.83 + 0.07 = 0.93](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20a%20%2B%20b%20%2B%20A%20%5Ccap%20B%20%3D%200.03%20%2B%200.83%20%2B%200.07%20%3D%200.93)
93% probability of a student taking a calculus class or a statistics class