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3 years ago

What is the slope of the line that passes through the points (3, 8) and (8, 13) ?(

Mathematics

1 answer:

Kryger [21]3 years ago

5 0

Answer:

The slope of the line would be 1

Step-by-step explanation:

To do this, you would take the slope formula, (Y2-Y1)/(X2-X1)

Next we would plug in the points of the line

(13-8)/(8-3)

5/5

1/1

Therefore, the slope of the line is 1.

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Sorry, I'm going to need a more accurate question. How many kids are there in total?

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3 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

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3 years ago

Sonal went to school for 219 days in a full year. if her attendance is 75 percent find the number of days on which the school wa

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Sonal went to school for 219 days in a full year. if her attendance is 75 percent find the number of days on which the school was open

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3 years ago

In the following exercises, multiply the binomials. Use any method.<br> 241. (x + 8)(x + 3)

Lelu [443]

Answer:

Hence the expression $(x+8)(x+3)=x^{2}+11 x+24$ .

Step-by-step explanation:

- The given expression is (x+8)(x+3).

- We have to multiply the given expression.

- Multiply the (x+8) by 3 , multiply the (x+8) by x then add like terms.

$\begin{array}{r}x+8 \\\underline {\times \quad x+3} \\3 x+24 \\\underline {x^{2}+8 x+24} \\x^{2}+11 x+24\end{array}$

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1 year ago

What is the value of x so that the line segment with endpoints W(x, −2) and X(5, −4) is parallel to the line segment with endpoi

professor190 [17]

Uhhhh I don't think that the correct answer.
First, find the gradient of the line segment.
Gradient = Rise/Run = (2-6)/(2-5) = 4/3.
Since the other line segment is parallel to this line segment, their gradients are the same.
That means (-2+4)/(x-5) = 4/3.
2/(x-5) = 4/3
It is obvious x = 6.5

7 0

3 years ago