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3 years ago

Help with 13-16 please

Mathematics

1 answer:

zzz [600]3 years ago

6 0

Ok hold on... for 13, do 1000/1 times 2/3 then simplify. U know how to do that? If not I'll tell u wen I'm done with 14 because, sadly I'm only a 7th grader and all I know is 13 and 14. For 14, do 4/1 times 5/2 then simplify.

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3 years ago

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Lena [83]

Answer:

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3 years ago

In a board game, students draw a number do not replace it, and then draw a second number. Determine the probability of each even

murzikaleks [220]

The figure depicting the board game is attached below.

Answer:

Step-by-step explanation:

Kindly note that selections done without replacement.

Count of numbers on the board game = 8

Count of odd numbers = (1, 9, 1) = 3

Count of digit 6 = 3

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Hence,

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3 years ago

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aliya0001 [1]

No, your answer are wrong (I assume that the question asks to simplify the roots). You can only remove (their square is placed in from of the root and multiplied by it) the numbers from the root that are squares, the lest must stay, like this:

$\sqrt{14} = \sqrt{2*7} ,$ no roots are among the factors, nothing can be removed
$\sqrt{14} = \sqrt{2*7} ,$ nothing can be removed
$-\sqrt{39} = -\sqrt{3*13}$ nothing can be removed
$-\sqrt{56} = -\sqrt{2*2*2*7}=-2\sqrt{14} ,$
$-\sqrt{77} = -\sqrt{11*7} ,$ nothing can be removed
$\sqrt{41} = \sqrt{41} ,$ nothing can be removed
$\sqrt{21} = \sqrt{3*7} ,$ nothing can be removed
$- \sqrt{65} = -\sqrt{5*13} ,$ nothing can be removed
$-\sqrt{12} = -\sqrt{2*3*4} =-2\sqrt{4},$
$\sqrt{13} = \sqrt{13} ,$ nothing can be removed
$\sqrt{32} = \sqrt{4*4*2} =4\sqrt{2},$
$\sqrt{47} = \sqrt{47} ,$ (47 is prime) nothing can be removed
$-\sqrt{99} = -\sqrt{9*11}= -3\sqrt{11} ,$

4 0

3 years ago

NEED HELP! Have no idea what his is?? 50 points

soldi70 [24.7K]

Well i have to say is that PEMDAS exponents first. Hope this helps.

5 0

4 years ago

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