I assume there are some plus signs that aren't rendering for some reason, so that the plane should be
.
You're minimizing
subject to the constraint
. Note that
and
attain their extrema at the same values of
, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is
Take your partial derivatives and set them equal to 0:
Adding the first three equations together yields
and plugging this into the first three equations, you find a critical point at
.
The squared distance is then
, which means the shortest distance must be
.
Since both values are positive, it is in quadrant 1
Assuming the series is
The series will converge if
We have
So the series will certainly converge if
, but we also need to check the endpoints of the interval.
If
, then the series is a scaled harmonic series, which we know diverges.
On the other hand, if
, by the alternating series test we can show that the series converges, since
and is strictly decreasing.
So, the interval of convergence for the series is
.
6 because the 36 is r² where r is the radius, r² = 36; we have to isolate the r so it's by its self, so square root both sides, r = 6
Answer:
-3/1
Step-by-step explanation: