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3 years ago

Solve for x:

Mathematics

1 answer:

Dafna11 [192]3 years ago

8 0

Step-by-step explanation:

5*(4x+8)=6*(2x+3)

20x+40=12x+18

20x _12x= 18_40

8x = _22

x=_22/8

x= _11/4

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Rhonda sells textbooks her paycheck is found using the formula p=30b+15, where is the number of textbooks she sells. solve the f

Alex73 [517]

The answer is b=p-1/2, the work is below

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3 years ago

What two numbers add to 8 and multiply to 28

anygoal [31]

Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28

x= $\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}$
x= $\frac{8+/- \sqrt{-48} }{2}$
x= $\frac{8+/- 4 \sqrt{-3} }{2}$
x= $4+/- 2 \sqrt{-3}$
x= $4+/- 2i \sqrt{3}$
there are no real numbers that satisfy this

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3 years ago

How to model 4÷2/3??

stealth61 [152]

Answer:

We have 4 x ( 3 / 2 ) = 12 / 2 = 6;

Step-by-step explanation:

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3 years ago

What is 15+cj to the 3rd power when c=6 and j=5

exis [7]

1)( 15+cj)^3 for j = 5 and c = , ( 15+6*5)^3 = (45)^3 = 91125

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3 years ago

An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insu

ankoles [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly selected customer insures exactly one car, and that car is not a sports car?

Answer:

P( X' ∩ Y' ) = 0.205

Step-by-step explanation:

Let X is the event that the customer insures more than one car.

Let X' is the event that the customer insures exactly one car.

Let Y is the event that customer insures a sport car.

Let Y' is the event that customer insures not a sport car.

From the given information we have

70% of customers insure more than one car.

P(X) = 0.70

20% of customers insure a sports car.

P(Y) = 0.20

Of those customers who insure more than one car, 15% insure a sports car.

P(Y | X) = 0.15

We want to find out the probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

P( X' ∩ Y' ) = ?

Which can be found by

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

From the rules of probability we know that,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y ) (Additive Law)

First, we have to find out P( X ∩ Y )

From the rules of probability we know that,

P( X ∩ Y ) = P(Y | X) × P(X) (Multiplicative law)

P( X ∩ Y ) = 0.15 × 0.70

P( X ∩ Y ) = 0.105

So,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )

P( X ∪ Y ) = 0.70 + 0.20 - 0.105

P( X ∪ Y ) = 0.795

Finally,

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

P( X' ∩ Y' ) = 1 - 0.795

P( X' ∩ Y' ) = 0.205

Therefore, there is 0.205 probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

6 0

2 years ago