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3 years ago

Pls help with #8 thx!

Mathematics

1 answer:

liberstina [14]3 years ago

8 0

I did on the other one

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A package delivery company experiences high variability in daily customer demand, which in turn results in high variability in t

Ilya [14]

Solution :

Let :

X = number of overtime hours

S = total weekly salary

S = $12 \times 40 + 18 \times X$

S = 480 + 18X

E(S) = $480 + 18 \times E(X)$

$E(S) = 480 + 18 \times 15$

= 750

Mean of S = 750

Var (S) = $18^2 \times Var(X)$

Var(S) = $18^2 \times 4^2$

= 5184

Variance of S = 5184

The standard deviation equals square root of 5184 = 72

4 0

3 years ago

In the right triangle shown, \angle B = 60^\circ∠B=60

Liono4ka [1.6K]

Answer:

Part 1) $AC=6\sqrt{3}\ units$

Part 2) $AC=12\sqrt{3}\ units$

Step-by-step explanation:

I will analyze two problems

see the attached figure to better understand the problem

Problem 1

The hypotenuse is the segment AB and the right angle is C

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(60^o)=\frac{AC}{12}$

Remember that

$sin(60^o)=\frac{\sqrt{3}}{2}$

substitute

$\frac{\sqrt{3}}{2}=\frac{AC}{12}$

$AC=6\sqrt{3}\ units$

Problem 2

The hypotenuse is the segment BC and the right angle is A

we know that

In the right triangle ABC

$tan(B)=\frac{AC}{AB}$ ---> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(60^o)=\frac{AC}{12}$

Remember that

$tan(60^o)=\sqrt{3}$

substitute

$\sqrt{3}=\frac{AC}{12}$

$AC=12\sqrt{3}\ units$

5 0

3 years ago

How many terms are in the expression -6+8-10x+12-r

xxTIMURxx [149]

Answer:

3 terms

Step-by-step explanation:

10x

-6+8+12 (constant)

4 0

4 years ago

Which of the following values can be found by using the formula √1+cos^2 0?

Sati [7]

Let's check

Remove root over and simplify 1+cot²Ø

1+cos²theta/sin²theta
sin²Ø+cos²Ø/sin²Ø
1/sin²Ø
cosec²Ø

Putting root over

cscØ

Sin can be found also along with csc

5 0

2 years ago

Given the pattern rule Tn=n2-1<br><br> what are the first 3 terms of the pattern

sergeinik [125]

Answer:

0, 3 , 8

Step-by-step explanation:

substitute n = 1, 2, 3 into the pattern rule

T₁ = 1² - 1 = 1 - 1 = 0

T₂ = 2² - 1 = 4 - 1 = 3

T₃ = 3² - 1 = 9 - 1 = 8

8 0

2 years ago