Ask question

Ask question

All categories

dimulka [17.4K]

2 years ago

15

Which statement correctly describe the data shown in the scatter plot?

1 answer:

sammy [17]2 years ago

5 0

Answer:

The scatter plot shows a negative association.

Step-by-step explanation:

You might be interested in

The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t

Doss [256]

Answer:

First Case:

$\displaystyle p=\frac{5}{2}\text{ and } d=-2$

Second Case:

$\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}$

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

$6p+2, 4p^2-10, \text{ and } 4p+3$

Since this is an arithmetic sequence, each subsequent term is <em>d</em> more than the previous term, where <em>d</em> is our common difference.

Therefore, we can write the second term as;

$4p^2-10=(6p+2)+d$

And, likewise, for the third term:

$4p+3=(6p+2)+2d$

Let's solve for <em>d</em> for each of the equations.

Subtracting in the first equation yields:

$d=4p^2-6p-12$

And for the second equation:

$2d=-2p+1$

To avoid fractions, let's multiply the first equation by 2. Hence:

$2d=8p^2-12p-24$

Therefore:

$8p^2-12p-24=-2p+1$

Simplifying yields:

$8p^2-10p-25=0$

Solve for <em>p</em>. We can factor:

$8p^2+10p-20p-25=0$

Factor:

$2p(4p+5)-5(4p+5)=0$

Grouping:

$(2p-5)(4p+5)=0$

Zero Product Property:

$\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}$

Then, we can use the second equation to solve for <em>d</em>. So:

$2d_1=-2p_1+1$

Substituting:

$\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}$

So, for the first case, <em>p</em> is 5/2 and <em>d</em> is -2.

Likewise, for the second case:

$\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}$

So, for the second case, <em>p </em>is -5/4, and <em>d</em> is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0

3 years ago

What is the length of leg s of the triangle below?

Andru [333]

Answer:

d

Step-by-step explanation:

x them up

4 0

3 years ago

Help with number 50 please. Thanks.

Blizzard [7]

Answer:

$d = 7 + 3\sqrt{3}$ and

$d = 7 - 3\sqrt{3}$

Step-by-step explanation:

To solve the equation, $d^2 - 14d - 22 = 0$ , using the quadratic formula,

Recall: quadratic formula = $\frac{-b ± \sqrt{b^2 - 4ac}}{2a}$

Where,

a = 1

b = -14

c = 22

Plug in your values into the formula and solve:

$\frac{-(-14) ± \sqrt{(-14)^2 - 4(1)(22)}}{2(1)}$

$\frac{14 ± \sqrt{196 - 88}}{2}$

$\frac{14 ± \sqrt{108}}{2}$

$d = \frac{14 + \sqrt{108}}{2}$

$d = \frac{14 + 6\sqrt{3}}{2}$

$d = (\frac{2(7 + 3\sqrt{3})}{2}$

$d = 7 + 3\sqrt{3}$

And

$d = \frac{14 - \sqrt{108}}{2}$

$d = \frac{14 - 6\sqrt{3}}{2}$

$d = (\frac{2(7 - 3\sqrt{3})}{2}$

$d = 7 - 3\sqrt{3}$

4 0

3 years ago

Please help i’ll give brainliest if you give a correct answer and show your work

ollegr [7]

1. You take 0.002 and multiply this by 0.2, then get your answer of 0.0004.

it would look like that (0.2) . (0.002)=0.0004

2. An area of a rectangle: a . b

a= 0.4km
b=0.07 km

a . b= 0.4km . 0.07km= 0.028 km^2

HOPE THIS HELPED !!!!!

4 0

3 years ago

Solve for x: 2x^2-x=3<br>Please show your work?

vagabundo [1.1K]

<span>2x^2-x=3
</span><span>2x^2-x - 3 = 0
</span><span>(2x - 3)(x + 1) = 0

2x - 3 =0
x = 3/2

x + 1 =0
x = -1

answer
</span>
x = -1 and x = 3/2

8 0

3 years ago