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dimulka [17.4K]
2 years ago
15

Which statement correctly describe the data shown in the scatter plot?

Mathematics
1 answer:
sammy [17]2 years ago
5 0

Answer:

The scatter plot shows a negative association.

Step-by-step explanation:

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7 times the sum of a squared and b minus 4 times the sum of a squared and b
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7(a^2+b)-4(a^2+b)
7(a^2)+7b-4(a^2)-4b
7a^2-4a^2+7b-4b
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3a^2+3b
4 0
3 years ago
Write a function rule for the table. <br><br>x<br>0<br>1<br>2<br>3<br>f(x) <br>3<br>4<br>5<br>6
crimeas [40]
Y = x +3

Is your answer!
3 0
3 years ago
The area of a square sandbox is 83
elixir [45]
The answer to this question is 36. The formula to find area of a square is a squared. By equating that formula to 83 and taking the square root of both sides, we get the value of one side which is 9.1. Then we multiply that value by 4 because all sides of a square have equal values. This our answer becomes 36.4 which is rounded to 36.
8 0
3 years ago
Fill in the table using this function rule.<br> y=-3x + 5
zhannawk [14.2K]

Answer:

y=-3(-4)+5,,,, you get y=12+5  y=17

y=-3(-2)+5,,,, you get y=6+5  y=11

y=-3(0)+5,,,, you get y=0+5  y=5

y=-3(2)+5,,,, you get y=-6+5 y=-1

Step-by-step explanation:

<h2><u><em>hope it helps:)</em></u></h2>
8 0
3 years ago
Use Newton's method to approximate a root of the equation 3x^(7) + 2x^(4) + 2 = 0 as follows. Let x1 = 3 be the initial approxim
Maurinko [17]

Answer:

x_{2}\approx 2.59, x_{4}\approx 4.3

Step-by-step explanation:

1) Given that the formula for the Newton Method is:

x_{n+1}=x_{n}-\frac{f(x_{n})}{f(x_{n+1})}

2) The Function and its 1st derivative

f(x)=3x^{7}+2x^{4}+2\\f'(x)=21x^{6}+8x^{3}

3) Let's work with the first approximation. Plugging in in the function:

f(x)=3x^{7}+2x^{4}+2\Rightarrow f(3)=3(3)^{7}+2(3)^{3}+2\Rightarrow f(3)=6617\\f'(x)=21x^{6}+8x^{3}\Rightarrow f'(3)=21(3)^{6}+8(3)^{4}\Rightarrow f'(3)=15957\\\\x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\Rightarrow x_{2}=x_{1}-\frac{f(x_{1})}{f'(x_{1})}\\x_{2}=3-\frac{6617}{15957}\Rightarrow x_{2}\approx 2.59\\\\

4) To approximate the other root x

f(x)=3x^{7}+2x^{4}+2\Rightarrow f(5)=3(5)^{7}+2(5)^{3}+2\Rightarrow f(5)=234627\\f'(x)=21x^{6}+8x^{3}\Rightarrow f'(5)=21(5)^{6}+8(5)^{4}\Rightarrow f'(5)=333125\\\\x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\Rightarrow x_{4}=x_{3}-\frac{f(x_{1})}{f'(x_{1})}\\x_{4}=5-\frac{234627}{333125}\Rightarrow x_{4}\approx 4.3

5 0
3 years ago
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