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just olya [345]
3 years ago
8

Plz help me I’m not good at math

Mathematics
2 answers:
grigory [225]3 years ago
6 0

Answer:

second one

Step-by-step explanation:

am pretty sure

andrezito [222]3 years ago
6 0

Answer:

8x - 4y = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 and c = - \frac{3}{4} , then

y = 2x - \frac{3}{4} ← in slope- intercept form

Multiply through by 4 to clear the fraction

4y = 8x - 3 ( subtract 4y from both sides )

0 = 8x - 4y - 3 ( add 3 to both sides )

3 = 8x - 4y , or

8x - 4y = 3 ← in standard form

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PLEASE HELP :)
Gnom [1K]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of
Effectus [21]

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = <u><em>the blood platelet counts of a group of women</em></u>

So, X ~ Normal(\mu=257.62, \sigma^{2} =62.1^{2})

Now, the empirical rule states that;

  • 68% of the data values lie within the 1 standard deviation of the mean.
  • 95% of the data values lie within the 2 standard deviations of the mean.
  • 99.7% of the data values lie within the 3 standard deviations of the mean.

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

       z-score of 443.9 =  \frac{X-\mu}{\sigma}

                                   =  \frac{443.9-257.62}{62.1}  = 3

       z-score of 71.3 =  \frac{X-\mu}{\sigma}

                                =  \frac{71.3-257.62}{62.1}  = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

5 0
3 years ago
Wilma earns $9 per hour at her job. Then she spent $15 on a birthday gift for her best friend. Write an expression to represent
frozen [14]

Answer:

Wilma has $12.

Step-by-step explanation:

Since we don't know how many hours she worked, we know that Wilma earned 9x dollars at her job. Then she spends $15, so we can just subtract 15 from 9x.

9x-15

We can just replace the x with 3 to get:

27-15\\12

Hence, Wilma has $12.

3 0
3 years ago
Read 2 more answers
What is this number in standard form?
AleksAgata [21]

Answer:

Step-by-step explanation:

400+10+330+55,000

3 0
3 years ago
Read 2 more answers
laboratory tests show that the lives of light bulbs are normally distributed with a mean of 750 hours and a standard deviation o
Angelina_Jolie [31]

Answer:

0.13591

Step-by-step explanation:

What we do here is find a score of both values;

Mathematically;

z-score = (x - mean)/SD

for 825, we have (825-750)/75 = 1

For 900, we have (900-750)/75 = 150/75 = 2

So the probability we want to find is;

P(1<x<2) = P(x<2) - P(x<1)

We use the standard table for this and we arrive at;

P(1<x<2) = 0.13591

3 0
3 years ago
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