Answer:
lies in the shaded regions of both the top and bottom inequalities
Step-by-step explanation:
For a point to be a solution of two inequalities, it must lie in both solution sets. It ...
lies in the shaded regions of both the top and bottom inequalities
8- perfect cube. 2×2×2=8
9-perfect square. 3×3=9
21- neither.
27- perfect cube. 3×3×3=27
1331- perfect cube. 11×11×11=1331
1332- neither
100- perfect square. 10×10=100
1000- perfect cube. 10×10×10=1000
126- neither
125- perfect cube. 5×5×5=125
25-perfect square. 5×5=25
81-perfect square. 9×9=81
Answer:
T(3) = 13
Step-by-step explanation:
If we are trying to find the 3rd term of this <em>specific </em>sequence, then we simply plug in 3 as n.
T(3) = (3)² + 4
T(3) = 9 + 4
T(3) = 13
However, this isn't proper notation for an arithmetic or geometric sequence.