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kumpel [21]
3 years ago
5

A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F. The submarine dive

s down 115 feet deeper, and the water temperature drops by 2 1/5°F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.
Write the submarine’s initial elevation as a rational number.
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
5 0
-502.5-115=617.......
cestrela7 [59]3 years ago
4 0

Answer:

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 =

63 - 2 = 61

1/4 - 1/5 = 5/20 - 4/20 = 1/20

so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F

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<h3><u>Solution:</u></h3>

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\text { We get Surface area of new triangular prism }=2 b \times 2 h+2 \times 2 l \times 2 s+2 l \times 2 b

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