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kumpel [21]
4 years ago
5

A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F. The submarine dive

s down 115 feet deeper, and the water temperature drops by 2 1/5°F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.
Write the submarine’s initial elevation as a rational number.
Mathematics
2 answers:
Harlamova29_29 [7]4 years ago
5 0
-502.5-115=617.......
cestrela7 [59]4 years ago
4 0

Answer:

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 =

63 - 2 = 61

1/4 - 1/5 = 5/20 - 4/20 = 1/20

so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F

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Step-by-step explanation:

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Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
2 years ago
In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W
lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= \frac{1}{2}

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the  top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted  incorrectly in incorrect order

in \sum_{k =2}^{5}(k - 1) = 10 ways  

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= \frac{6 \times 10}{120}

=\frac{1}{2}

 

8 0
3 years ago
WILL UPVOTE!<br> Factor the expression.<br> 4r^2 − 49 =
chubhunter [2.5K]
Would it be
(2r-7)*(2r+7)

?
6 0
4 years ago
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